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3 years ago

Which energy transformation occurs when you light a gas burner?

Physics

1 answer:

Eddi Din [679]3 years ago

3 0

Answer:

Chemical energy to thermal(heat) energy

Explanation:

A gas burner contains chemical hydrocarbon such as methane, this methane is highly flammable.

The gas burner which contains methane when lighted up converts the chemical energy in the chemical to heat energy through the fire it produces. The fire then helps in heating up the surface it is applied to.

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A ball is thrown upward with an initial velocity of 12.1 m/s. How long will it take to reach a velocity of -24.5 m/s?

Rainbow [258]

<h3><u>Answer;</u></h3>

= 3.73 seconds

<h3><u>Explanation;</u></h3>

Using the equation;

v = u + at

where v is the final velocity, u is the initial velocity and a is the acceleration due to gravity (-g) and t is the time taken.

Therefore;

v = u - gt

Thus;

v = 24.5 m/s, u = 12.1 m/s, a = -g = 9.8 m/s²

-24.5 m/s = 12.1 - 9.8 × t

36.6 = 9.8 t

t = 36.6/9.8

= 3.73 seconds

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3 years ago

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Answer:

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Explanation:

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2 years ago

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When organic polymers joined together on early earth, they formed ______? Protons Protobionts Monomers Plankton

Sidana [21]

I think the answer would be protons

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3 years ago

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A spring with a mass of 5 Kg has natural length 0.5m. A force of 35.6 N is required to maintain it stretched to a length of 0.5m

aleksandrvk [35]

Answer:

Explanation:

force constant of spring k = force / extension

= 35.6 / 0.5

k = 71.2 N / m

angular frequency ω of oscillation by spring mass system

$\omega = \sqrt{\frac{k}{m} }$

where m is mass of the body attached with spring

Putting the values

$\omega = \sqrt{\frac{71.2}{5} }$

ω = 3.77 radian / s

The oscillation of the mass will be like SHM having amplitude of 0.5 m and angular frequency of 3.77 radian /s . Initial phase will be π / 2

so the equation for displacement from equilibrium position that is middle point can be given as follows

x = .5 sin ( ω t + π / 2 )

= 0.5 cos ω t

= 0.5 cos 3.77 t .

x = 0.5 cos 3.77 t .

8 0

3 years ago

A high diver of mass 51.7 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If he

zmey [24]

Answer:

851.33 N

Explanation:

Using newton;s equation of motion,

v² = u² + 2gh ......... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, h = height

Given: u = 0 m/s(from rest), h = 10 m g = 9.8 m/s².

Substitute into equation 1

v² = 0² + 2(9.8)(10)

v² = 196

v = √196

v = 14 m/s.

Note: As the Diver touches the water, u = 14 m/s and v = 0 m/s( stopped)

Using,

d = (v+u)t/2 .............. equation 2

Where d = distance moved by the diver in water before its motion stopped, t = time taken before it comes to rest

Given: v = 0 m/s, u = 14 m/s t = 2.10 s

Substitute into equation 2

d = (0+14)2.1/2

d = 14.7 m.

Finally

work done by the water to stop the diver = potential energy of the diver

F×d = mgh'................Equation 3

Where F = force of the diver in water, d = distance of the diver in the water, m = mass of the diver, g = acceleration due to gravity, h' = height of the diver from the point of fall to the point where he comes to rest

making F the subject of the equation,

F = mgh/d ............ Equation 4

Given: m = 51.7 kg, h = 10 m, g = 9.8 m/s², d = 14.7 m.

Substitute into equation 4

F = 51.7(10+14.7)(9.8)/14.7

F = 851.33 N

Hence the upward force the water exert on her = 851.33 N

8 0

3 years ago

Which energy transformation occurs when you light a gas burner?​

Which energy transformation occurs when you light a gas burner?