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3 years ago

Match the description with either a dehydration reaction or a hydrolysis reaction.

Chemistry

1 answer:

Gelneren [198K]3 years ago

6 0

Answer:

1) Hydrolysis

2)Dehydration

3)Dehydration

4)Hydrolysis

Explanation:

Hydrolysis is the chemical breakdown of substances by water and depends on the chemistry, solubility, pH, and the oxidation–reduction (Eh or redox) potential of compound

<em>https://www.sciencedirect.com/topics/earth-and-planetary-sciences/hydrolysis</em>

With hydrolysis water will be a reactant, not a product, and is associated with breaking down substances. Hence 1 and 4 being a Hydrolysis reaction.

Dehydration on the other hand, is defined as :

In a dehydration reaction, either a hydroxyl group from one molecule combines with a hydrogen atom from the other molecule, or two hydrogen atoms from one molecule combine with an oxygen atom on the other molecule. In either case, water is released, and the two molecules are joined together.

https://www.albert.io/blog/dehydration-synthesis-ap-biology-crash-course/

Therefore it is associated with creating a bond of sorts, and water is a product, which is why 2 and 3 are dehydration.

Hope this helps!

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What is the freezing point of an aqueous glucose solution that has 25.0 g of glucose?

LiRa [457]

Answer:

$T_f=-2.58\°C$

Explanation:

Hello,

In this case, we can compute the the freezing point depression by using the following formula:

$T_f-T_0=-i*m*Kf$

Whereas the freezing point of pure water is 0 °C van't Hoff factor for glucose is 1, the molality is computed as shown below and the freezing point constant of water is 1.86 °C/m:

$m=\frac{25.0g\ glucose*\frac{1mol\ glucose}{180g\ glucose} }{100g*\frac{1kg}{1000g} }\\ \\m=1.39m$

Thus, the freezing point of the solution is:

$T_f=T_0-i*m*Kf\\\\T_f=0\°C-1*1.39m*1.86\frac{\°C}{m}\\ \\T_f=-2.58\°C$

Regards.

4 0

4 years ago

How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?

ankoles [38]

The chemical reaction equation for this is

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6,

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x $\frac{1 mole XeF6}{3 moles H2}$ x $\frac{245.28 g XeF6}{1 mole XeF6}$ = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.

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4 years ago

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slava [35]

Answer:

Explanation:

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4 years ago

Whenever energy is ______ from one form to another, some of that energy is lost by being changed into heat.

schepotkina [342]

Whenever energy is converted from one form to another, some of that energy is lost by being changed into heat.

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3 years ago

write a paragraph to explain how the transformation of water from one state of matter to another is important for the water cycl

Westkost [7]

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3 years ago