-- The product of their two masses (no matter what
the individual masses happen to be),
-- The distance between the centers of mass of the two masses.
Nothing else affects the force of gravity between two objects,
and nothing in between them can 'shield' or block it.
Answer:
The ball will hit the ground 108.25 m down the field
Explanation:
To determine how far down the field the ball will hit the ground, that is the Range of the ball. From formula to calculate Range in projectile motion,
Where R is the Range
u is the initial velocity
θ is the angle of projection
and g is acceleration due to gravity (Take g = 9.8 m/s²)
From the question,
Initial velocity, u = 35 m/s
Angle, θ = 60°
Putting these values into the equation, we get
Hence, the ball will hit the ground 108.25 m down the field.
Answer:
Kinetic energy
Explanation:
The energy associated with an object's motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy.
Answer:
Potential energy at top of hill = m*g*h = 1000*9.81*90 = 882,900 Joules = 883kJ (corrected to 3 significant figures)
Kinetic energy at foot of hill = 1/2 mv^2 = 1/2*1000 (40)^2 = 800,000 J
efficiency of energy transfer = output/input*100% = 800,000/883,000 *100% = 90.6% (Answer)
Note that the "lost" energy during the journey is largely due to friction along the road and air resistance.
Because of energy 'losses' during transfer, the first hill will be the highest to accommodate the 'loss,' bearing in mind that the initial potential energy is m*g*h, with both m and g being constant the only one that can vary to accommodate the energy 'loss' is the height, which means that with each successive hill the height that the mass will rise will be decreasing. Hence the first hill will of necessity be the highest
Explanation:
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