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2 years ago

The materials in the pictures below trap air. They act as as good insulator against...

Physics

2 answers:

olga nikolaevna [1]2 years ago

6 0

Answer:

Girl its Radiation

Hope this helps you!!

WINSTONCH [101]2 years ago

3 0

Answer:

a.its simply radaition

Explanation:

hope it helps you..

follow me for more help sir:)

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In a local bar, a customer slides an empty beer mug down the counter for a refill. the height of the counter is 1.15 m. the mug

yarga [219]

A. Let’s say the horizontal component of the velocity is vx and the vertical is vy. 
Initially at t=0 (as the mug leaves the counter) the components are v0x and v0y.
v0y = 0 since the customer slides it horizontally so applied force is in the x component only.

The equations for horizontal and vertical projectile motion are:
x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2

Setting the origin to be the end corner of the counter so that x0=0 and y0=0, hence:

x = v0x t

y = - 1/2 g t^2

Given value are: x=1.50m and y=-1.15m (y is negative since mug is going down)

1.50m = v0x t ----> v0x= 1.50/t

-1.15m = -(1/2) (9.81) t^2 -----> t =0.4842 s

Calculating for v0x:

v0x = 3.10 m/s

B. v0x is constant since there are no other horizontal forces so, v0x=vx=3.10m/s

vy can be calculated from the formula:

vy = v0y + at where a=-g (negative since going down)

vy = -gt = -9.81 (0.4842)

vy = -4.75 m/s

Now to get the angle below the horizontal, tan(90-Ø) = -vx/vy

tan(90-Ø )= 3.1/4.75

Ø = 56.87˚ below the horizontal

4 0

3 years ago

Read 2 more answers

a satellite is traveling in a orbit around the earth. what change would cause it to experience more gravitational force from the

never [62]

The correct answer is:
A. orbiting closer to the earths surface.

In fact, the gravitational force exerted by the Earth on the satellite is
 $F=G \frac{Mm}{r^2}$
where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface

We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.

7 0

2 years ago

A car travels 10 meters east in 4 seconds. What is the car's velocity? *

MrMuchimi

Answer:

your velocity is 2.5 m/sec

6 0

2 years ago

Read 2 more answers

A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10×10^{4} 4 m/s^{2} 2 , and 1.85 ms (1

Paha777 [63]

Answer:

u = - 38.85 m/s^-1

Explanation:

given data:

acceleration = 2.10*10^4 m/s^2

time = 1.85*10^{-3} s

final velocity = 0 m/s

from equation of motion we have following relation

v = u +at

0 = u + 2.10*10^4 *1.85*10^{-3}

0 = u + (21 *1.85)

0 = u + 38.85

u = - 38.85 m/s^-1

negative sign indicate that the ball bounce in opposite directon

6 0

2 years ago

An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res

murzikaleks [220]

Answer:

(a) $V=11.86\ V$

(b) $V=9.76\ V$

Explanation:

Electric Circuits

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

$V=R.I$

(a) The electromagnetic force of the battery is $\varepsilon =12.6\ V$ and its internal resistance is $R_i=0.06\ \Omega$ . Knowing the equivalent resistance of the headlights is $R_e=5.2\ \Omega$ , we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

$\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)$

Solving for i

$\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A$

i=2.28\ A

The potential difference across the headlight bulbs is

$V=\varepsilon -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V$

$V=11.86\ V$

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

$V=\varepsilon -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V$

5 0

2 years ago