An aqueous solution of potassium hydroxide is standardized by titration with a 0.187 M solution of nitric acid. If 22.7 mL of ba
se are required to neutralize 29.4 mL of the acid, what is the molarity of the potassium hydroxide solution?
1 answer:
Answer:
Explanation:
29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .
moles contained in nitric acid solution
= .0294 x .187 moles
= 5.5 x 10⁻³ moles
This must have been reacted with same amount of moles of base
moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles
molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³
= .24 M .
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