Answer:
103.4 moles of hydrogen
Explanation:
Given data:
Moles of C₁₂H₂₂O₁₁ = 4.70 mol
Number of moles of hydrogen present = ?
Solution:
one mole of C₁₂H₂₂O₁₁ contain 22 moles of hydrogen. Thus in order to determine total number of moles in 4.70 moles of C₁₂H₂₂O₁₁ we will multiply the 22 moles of hydrogen with 4.70 moles of C₁₂H₂₂O₁₁.
1 mole of C₁₂H₂₂O₁₁ = 22 moles of Hydrogen
4.70 × 22 moles
103.4 moles of hydrogen
Answer:
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Explanation:
Answer:
Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.
Explanation:
From the given,
Mass of sodium carbonate 
= 8.85 g
Loss mass 
= 1.28 g
Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g
Therefore, the compound has only one water molecule.
Molecular formula of the compound is 
an name of the compound is <u>sodium carbonate mono hydrate.</u>
Hence, the type of the compound is Mono hydrate.
Explanation:
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