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Nata [24]
3 years ago
12

The length of a rectangle is given by (x+9) feet and the width is (x+2) feet. If the area is 60 square feet, what are the length

and width?
Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

The length of the rectangle  = 12 feet

The width of the rectangle  = 5 feet

Step-by-step explanation:

<u>Step(i):-</u>

Given that the length of the rectangle = (x+9)feet

Given that the width of the rectangle = (x+2)feet

Area of the rectangle = 60 square feet ...(i)

we know that

Area of the rectangle = length × width

                                     = (x+9)(x+2) ....(ii)

Equating (i) and (ii) , we get

                   (x+9)(x+2) = 60

            ⇒ x² + 2x +9 x +18 =60

            ⇒ x² +11 x +18-60 =0

          ⇒  x² + 11 x -42 =0

          ⇒ x² +14 x -3 x - 42 =0

        ⇒  x (x+14) -3(x+14) =0

          ⇒ (x -3) ( x+14) =0

        ⇒  x -3 =0 and x+14 =0

     ⇒   x=3 and x=-14

<u><em>step(ii):-</em></u>

we choose value x =3

The length of the rectangle = (3+9) = 12 feet

The width of the rectangle = (3+2) = 5 feet

<u><em>Final answer:-</em></u>

The length of the rectangle  = 12 feet

The width of the rectangle  = 5 feet

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