Can someone pls answer this question

Consider the hydrogen atom as described by the Bohr model. The nucleus of the hydrogen atom is a single proton. The electron rot

lina2011 [118]

Explanation:

It is given that the atom is hydrogen. And, its electron rotates in n = 5 orbit with angular speed $3.3 \times 10^{14} rad/s$ .

Radius of circular path = $1.32 \times 10^{-9}$ m

Hence, first calculate the tangential speed as follows.

Tangential speed = radius × angular speed

= $4.356 \times 10^{5} m/s$

As formula to calculate time period is as follows.

T = $1.5211 \times 10^{-16} \times \frac{n^{3}}{z^{2}}$ sec

Also, frequency $(\nu)$ = $\frac{1}{T}$

So, for n = 5 and z = 1 the value of frequency is as follows.

frequency $(\nu)$ = $\frac{1}{1.5211 \times 10^{-16}} \times \frac{z^{2}}{n^{3}}$

= $\frac{1}{1.5211 \times 10^{-16}} \times \frac{1}{(5)^{3}}$

= $5.259 \times 10^{13}$ Hz

As formula to calculate centripetal acceleration is as follows.

$a_{c} = \frac{v^{2}}{r}$

where, v = linear speed

r = radius

v = $2.165 \times 10^{6} \times \frac{z}{n}$

= $2.165 \times 10^{6} \times \frac{1}{5}$

= $4.3 \times 10^{5} m/s$

Hence, the centripetal acceleration will be as follows.

$a_{c} = \frac{v^{2}}{r}$

= $\frac{(4.3 \times 10^{5})^{2}}{1.32 \times 10^{-9}}$

= $1.4 \times 10^{20} m/s^{2}$

Thus, we can conclude that the electron's centripetal acceleration is $1.4 \times 10^{20} m/s^{2}$ .

6 0

3 years ago

What is a heterogeneous mixture?

Setler [38]

Answer:

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture

6 0

3 years ago

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How much heat energy is required to raise the temperature of 0.367 kg of copper from 23.0 C to 60.0 C ? The specific heat of cop

mojhsa [17]

Note: We must keep the units we use consistent. The Cp is given in cal/gC so we will use cal for energy, grams for mass and C for temperature.
1)
Heat supplied can be calculated using:
Q = mCpΔT; where m is the mass, Cp is the specific heat capacity and ΔT is the temperature change.
Q = 367 x 0.092 x (60 - 23)
Q = 125 Cal

2)
Using the same equation:
125 = 60 x 0.092 x (T - 23)
T = 45.6 C

5 0

3 years ago

An organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classifie

Basile [38]

Answer:

c. alkyne.

Explanation:

Hello there!

In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.

In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.

Regards!

3 0

3 years ago

Find the volume of a rectangular prism that is 25 cm by 10 cm by 15 cm. height length

Stolb23 [73]

Answer:

3750 cm.

Explanation:

You multiply the three side measurements to find the volume.

25cm·10cm·15cm

375cm·10cm

3750 cm.

Hope this helps!

4 0

3 years ago

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