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Marina86 [1]
3 years ago
13

A sample of rubidium contains two different isotopes. 72.15% of the sample

Chemistry
1 answer:
Leona [35]3 years ago
4 0

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

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1 year ago
25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
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calculation

write the equation for reaction

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moles =molarity x volume

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