(a) The time for the capacitor to loose half its charge is 2.2 ms.
(b) The time for the capacitor to loose half its energy is 1.59 ms.
<h3>
Time taken to loose half of its charge</h3>
q(t) = q₀e-^(t/RC)
q(t)/q₀ = e-^(t/RC)
0.5q₀/q₀ = e-^(t/RC)
0.5 = e-^(t/RC)
1/2 = e-^(t/RC)
t/RC = ln(2)
t = RC x ln(2)
t = (12 x 10⁻⁶ x 265) x ln(2)
t = 2.2 x 10⁻³ s
t = 2.2 ms
<h3>
Time taken to loose half of its stored energy</h3>
U(t) = Ue-^(t/RC)
U = ¹/₂Q²/C
(Ue-^(t/RC))²/2C = Q₀²/2Ce
e^(2t/RC) = e
2t/RC = 1
t = RC/2
t = (265 x 12 x 10⁻⁶)/2
t = 1.59 x 10⁻³ s
t = 1.59 ms
Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.
Learn more about energy stored in capacitor here: brainly.com/question/14811408
#SPJ1
Answer:
Explanation:
Let us calculate gallon used in one hour .
It travels 70 miles in one hour
in 70 miles it uses 70 / 34 gallons of fuel
70 / 34 gallons = 70 / 34 x 3.7854 kg
= 7.8 kg
heat generated = 7.8 x 44 x 10⁶ J
= 343.2 x 10⁶ J
This is heat generated in one hour
heat generated in one second = 343.2 x 10⁶ / 60 x 60 J/s
= 95.33 x 10³ J /s
= 95.33 kW.
Given:
The speed of sound is 340 m/s
Time for the echo is 5.2 s.
Let h = the depth of the canyon.
Because the sound of your voice travels to the bottom of the canyon and back to your ear, the total distance traveled is 2h.
By definition,
distance = velocity * time.
Therefore
2h = (340 m/s)*(5.2 s) = 1768 m
h = 884 m
Answer: The depth is 884 m.
Answer: 258.7 J
Explanation:
Velocity of object V=5m/s
Mass ; 5kg
Height; h=4m
Mechanical energy is equal to sum of kinetic and potential energy
E=K+Ep
Kinetic energy is calculeted using; K=m*V²/2
Potential energy is calculated using : Ep=m*G*h
-------------------------------------------------------------------------
V=5m/s
m=5kg
h=4m
E=K+Ep
E=m*V²/2+m*G*h
E=5kg*(5m/s)²/2+5kg*9.81m/s²*4m
E=62.5J+196.2J
E=258.7 J
