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Varvara68 [4.7K]
3 years ago
10

An electric field has a positive test charge of 5.00 C placed in it. The force on the test charge is

Physics
1 answer:
butalik [34]3 years ago
7 0

Answer:

yes

Explanation:

this means the answer is yes

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describe what is meant by "a constant change of direction".Identify whether the examples provided show a constant change of dire
liraira [26]

"Constant change of direction" simply means on a curve.

The examples provided don't show a durn thing.

7 0
3 years ago
Any clue on this one
rodikova [14]

Answer: First option

Explanation: The higher the frequency, the higher the energy.

λν=c where λ is the wavelength, ν is the frequency and c is the speed of light. So when wavelength decreases, v increases and so does energy.

An AM radio wave has a very long wavelength. It therefore has a very low frequency and low energy.

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3 0
3 years ago
Rutherford's gold-foil experiment led him to conclude that
erica [24]

Answer:

C. a dense region of positive charge existed somewhere in the atom.

Explanation:

Physicist Ernest Rutherford created the gold foil experiment in which he shot a beam of alpha particles at a sheet of gold foil, which then sent a  few of the particles flying after they were deflected. Based on the information gathered after completing this experiment, Rutherford concluded that a dense region of positive charge existed somewhere in the atom.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
APEX What is one advantage of using primary sources when doing research on an
MissTica

Answer:

C

Explanation:

They are first hand sources so they are more reliable and detailed...

4 0
3 years ago
The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po
creativ13 [48]

Answer:

The distance is  d = 1.5 *10^{15} \ km

Explanation:

From the question we are told that

        The smallest shift is d = 0.2 \ grid \ units

Generally a grid unit is  \frac{1}{10} of  an arcsec

  This implies that  0.2 grid unit is  k =  \frac{0.2}{10} = 0.02  \  arc sec

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

           d =  \frac{1}{k}

substituting values

           d =  \frac{1}{0.02}

           d = 50 \ parsec

Note  1 \ parsec  \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km

So  d = 50 * 3.08 *10^{13}

     d = 1.5 *10^{15} \ km

3 0
3 years ago
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