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To create the Lewis structure we need to take into account the octet rule: atoms tend to gain, lose or share electrons to complete their valence shell with 8 electrons.
C belongs to Group 4A in the periodic table so it has 4 valence electrons. It needs to share 4 pairs of electrons to complete the octet.
F belongs to Group 7A in the periodic table so it has 7 valence electrons. Each F needs to share 1 pair of electrons to complete the octet.
As a consequence, in CF₄, C will form a single bond with each F and all the octets will be complete.
The reaction is:
So for every molecule of nitrogen we need 3 molecules of hydrogen.
Now, we have 4 molecules of nitrgen, so if the total amount of nitrogen react we would need 4x3=12 molecules of hydrogen.
We know that there are only 9 molecules of hydrogen present, so it is not possible that all the nitrogen present react. Therefore the limiting reactant is hydrogen.
To answer how many molecules of ammonia (NH3) are produced we need to calculate the amount formed if all the hydrogen present reacts:
For every 3 molecules of hydrogen 2 molecules of ammonia are formed, so for 9 molecules of hydrogen the molecules of ammonia formed are: 2x3=6.
To form 6 molecules of ammonia there are needed 6/2=3 molecules of nitrogen, so only one remains after the reaction.
To summerize:
• The number of molecules of ammonia formed are 6
,• The limiting reactant is hydrogen
,• The number of molecules remaining after the reaction are:
molecules of hydrogen: 0
molecules of nytrogen: 1