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3 years ago

How many moles of FeO are produced of 8 moles of SO2 are produced?

Chemistry

2 answers:

Harrizon [31]3 years ago

7 0

Answer: 0.091 moles

Explanation:

$2CuFeS_2+5O_2\rightarrow 2Cu+2FeO+4SO_2$

To calculate the moles, we use the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Molar mass of $SO_2$ = 44 g/mol

Putting values in above equation, we get:

$Moles=\frac{8g}{44g/mol}=0.182moles$

We are given that for 2 moles of $2CuFeS_2$ produces 2 moles of FeO and 4 moles of $SO_2$ are produced

By stoichiometry of the reaction,

if 4 moles of $SO_2$ are produced, 2 moles of FeO are produced.

So, 0.182 moles of $SO_2$ are produced= $\frac{2}{4}\times 0.182$ = 0.091 moles of FeO are produced.

Alecsey [184]3 years ago

4 0

4 moles as their raport is 4/2 or 2/1

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3 years ago

How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?

vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

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