Answer:
3.4 mT
Explanation:
L = 0.53 m
i = 7.5 A
Theta = 19 degree
F = 4.4 × 10^-3 N
Let B be the strength of magnetic field.
Force on a current carrying conductor placed in a magnetic field.
F = i × L × B × Sin theta
4.4 × 10^-3 = 7.5 × 0.53 × B × Sin 19
B = 3.4 × 10^-3 Tesla
B = 3.4 mT
Answer:
C and D
Explanation:
A: is a simple composition
B: is a single replacement
C: C is a double displacement
D: is a double replacement
That's false. The half-life of an unstable element
doesn't depend on its environment.
V^2 = vi^2 + 2as
vi = 0 in this case
a = 9.8 m/s^2
So,
V^2 = 2 * 9.8 * 490
v = 98.05 m/s
hope this helps