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g100num [7]
2 years ago
8

Explain what the international research team discovered and where this discovery is located in the body.

Physics
2 answers:
Alinara [238K]2 years ago
8 0

Answer:

They found a new sensory system in the human body, hiding in a network that runs through the blood vessels and sweat glands.

Explanation:

11111nata11111 [884]2 years ago
7 0

Answer:

They found a new sensory system in the human body, hiding in a network that runs through the blood vessels and sweat glands.

Explanation:

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Examples of forces in motion that you can see?
lidiya [134]

Answer:

tensional force

Explanation:

It usually exist in fluid or any liquid substance where by an object is put before it

e.g An ant can walk on water without submersed in it.

6 0
2 years ago
What is 1 + 2 -3 +5 - 10​
e-lub [12.9K]
-5 is the correct answer for this!
5 0
2 years ago
Explain diffraction at a single slit (light)
Leto [7]

Answer:

At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from   light coming from the center of the slit.

Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,

There will be no light on the screen at that particular point and thus there will be a dark fringe there.

That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.

4 0
1 year ago
What is the metric unit of weight? Gram/pound/Newton/milliliter
coldgirl [10]
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7 0
2 years ago
A battleship that is 6.00×107kg and is originally at rest fires a 1100-kg artillery shell horizontally with a velocity of 575 m/
mel-nik [20]

Answer:

Part a)

v = 0.0105 m/s

Part b)

E = 1.82 \times 10^8 J

Explanation:

As per momentum conservation we know that

P_1 = P_2

P_1 = m_1 v_1

P_2 = m_2v_2

here we know

m_1 = 6.00 \times 10^7 kg

v_1 =  ?

m_2 = 1100 kg

v_2 = 575 m/s

Part a)

now from above expression we can say

m_1v_1 = m_2v_2

(6.00 \times 10^7)(v) = (1100)(575)

v = 0.0105 m/s

Part b)

Now increase in the internal energy of the system

E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

E = \frac{1}{2}(6.00 \times 10^7)(0.0105)^2 + \frac{1}{2}(1100)(575^2)

E = 1.82 \times 10^8 J

7 0
3 years ago
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