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KengaRu [80]
3 years ago
12

How are the skeletal and circulatory systems alike?

Physics
2 answers:
alisha [4.7K]3 years ago
6 0
The bones in the skeletal system also work together with the circulatory system
Volgvan3 years ago
3 0

Explanation:

The calcified bones of our skeleton work with circulatory system. Marrow inside our bones helps to produce cell inside blood. Both red blood cell and white blood cell are produced in bones. Circulatory system delivers oxygenated blood into bones.

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When a warm air mass moves into an area where a cold air mass is located, it is called a(n) _____?
rusak2 [61]
It is called a warm front when a warm air mass moves into an area where a cold air mass is located based on the blanked sentence above. A warm front is a condition where a warm air mass is replacing a cold air in a place. The character of a warm front condition is an increasing in temperature of a place which is caused by the moving warm air mass<span>.</span>
8 0
4 years ago
A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m ​ 14, start fraction, start text, m, en
Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

​

 

=

Change in time

Change in velocity

​

=

Δt

v

f

​

−v

i

​

​

​

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

​

v, start subscript, f, end subscript, initial velocity v_iv

i

​

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

m

​

−(−14

s

m

​

)

​

=−2.0

s

2

m

​

​

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

​

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0
3 years ago
Why is it more difficult to lean over and push a heavy box across the floor than it is to attach a rope and pull the box at the
melisa1 [442]

Answer:

Case 1: <u>Pushing</u> Diagram 1

Leaning over and Pushing the heavy box from the floor, the push will be divided in to two parts, one is horizontal that can help the box move, and one is vertically downwards, which increases the downward force of the heavy object (an addition to the gravity) and thus increases friction, making it very hard to push.  When you push at certain angle, you are exhibiting two forces as shown in diagram 1.

  1. Horizontal force acting along the plane.
  2. Vertical force downward perpendicular to the surface.

Case 2: <u>Pulling</u> Diagram 2

Pulling on a rope similar object at the same angle, the pull can be divided into two parts, one is horizontal that can help the box move, and one is vertically upwards, which decreases the downwards force of the box (a subtraction in the gravity) and thus decreases friction, making it very easy to pull. When you pull at a certain angle, you are exhibiting two forces as shown in diagram 2.

  1. Horizontal force acting along the plane.
  2. Vertical force upward perpendicular to the surface.

So, in the case of pushing, it adds an extra weight on the object, which results in difficulty to push that object at the same angle.  In case of pulling, the upward perpendicular force, it tries to lift the  object upward and divided the weight partially. Thus making it easier to move the object at same angle.

8 0
3 years ago
Which of the following charts correctly compares plant and animal cells?
nadya68 [22]

Answer:

Wheres the charts??

Explanation:

7 0
3 years ago
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myrzilka [38]

Answer:

Mình cũng không biết làm bạn ơi =)))

Explanation:

6 0
3 years ago
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