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Natalka [10]
3 years ago
15

laser light sent through a double slit produces an interference pattern on a screen 3.0 m from the slits. If the eighth order ma

ximum occurs at an angle of 12.0, at what angle does the third order maximum occur
Physics
1 answer:
Xelga [282]3 years ago
8 0

Solution :

Given the laser light which is sent through the double slit produces an interference pattern on the screen placed 3  meters from the slits.

The 8th order maximum occurs at angle = 12

So,

$8^{th} \text{ order maxima} = d \sin \theta = m \lambda$      , m = 8

$d = \frac{8 \lambda}{\sin 12}$

$\frac{\lambda}{d}= \frac{\sin 12}{8}$

$3^{rd} \text{ order maxima}= d \sin \theta_2 = m_2 \lambda$

$\sin \theta_2 = \frac{m_2 \lambda}{d}=\frac{3 \lambda}{d}$ $=0.75\ {\sin 12}$

$\theta_2 = \sin^{-1}\left(0.75\ \sin 12\right)$

   $ = \sin^{-1}\left(0.155)$

   $=8.91^\circ$

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asambeis [7]

Answer:

The recoil speed of the man and rifle is v_{man}=0.016 ms^{-1}.

Explanation:

The expression for the force in terms of mg is as follows;

F=mg

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Rearrange the expression for mass.

m=\frac{F}{g}

Calculate the combined mass of the man and rifle.

m_{man,rifle}=\frac{650+25}{g}

Put g=9.8 ms^{-2}.

m_{man,rifle}=\frac{650+25}{9.8}

m_{man,rifle}=68.88 kg

The expression for the conservation of momentum is as follows as;

m_{man}u_{man}+m_{bullet}u_{bullet}=m_{man}v_{man}+m_{rifle}v_{man,rifle}

Here, m_{man,rifle} is the mass of the man and rifle,  m_{rifle} is the mass of the rifle,u_{man},u{bullet}  are the initial velocities of the man and bullet and v_{man},v{man,rifle} are the final velocities of the man and rifle and rifle.

It is given in the problem that a rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s.

Convert mass of rifle from gram to kilogram.

m_{bullet}=4.5 g

m_{bullet}=.0045 kg

Put m_{bullet}=.0045 kg,m_{man,rifle}=68.88 kg , u_{man,rifle}=0, v_{bullet}= 240 ms^{-1} and u_{bullet}=0.

m_{man}(0)+m_{bullet}(0)=(68.88)v_{man,rifle}+(.0045)(240)

0=(68.88)v_{man,rifle}+(.0045)(240)

0=(68.88)v_{man,rifle}+1.08

(68.88)v_{man,rifle}=\frac{-1.08}{68.88}

v_{man,rifle}=-0.016 ms^{-1}  

Therefore, the recoil speed of the man and rifle is v_{man}=0.016 ms^{-1}.

3 0
3 years ago
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likoan [24]
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7 0
3 years ago
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mariarad [96]

Answer:

kg·m/s

Explanation:

6 0
3 years ago
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A donkey starts from rest and accelerates for 6.7 s at a rate of 1.6 m/s².
vitfil [10]

The maximum speed of the donkey is 10.72m/s

The question is based on the principle of motion in one dimension and hence formulas of motion in one dimension can be applied.

It is given that donkey attains an acceleration of 1.6 m/s^2

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We use the formula v=u + at to find the fastest speed

v is the final or maximum speed

u is the initial speed which in this case is 0 as the donkey is at rest

a is the acceleration of the donkey

t is  the time taken in seconds

v = u + at

v= 0 + 1.6 x 6.7

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Hence the donkey obtains the speed of 10.72 m/s

For further reference:

brainly.com/question/24478168?referrer=searchResults

#SPJ9

3 0
2 years ago
What is the voltage of a motor that draws a current of 2 a and produces 240 w of power?
MA_775_DIABLO [31]
Here Power = Voltage * Current

So, Voltage = Power/Current

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In short, Your Final Answer would be: 120 Volts

Hope this helps!
8 0
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