descirbe the motion of the block oncw the rocket turned off. What would it take to get the block to acclereate again?

Physics

1 answer:

avanturin [10]3 years ago

3 0

Answer:

HW3 Motion (Ldimension _ obiecL acceleralions) Question rocket on the ground is launched with an acceleration of 40 m/s $ upward. seconds inlo the flight the engine shuts off: Assume there no air resistance. Preliminary questions The acceleraton of the rocket i5 40 mls/5. Do you have t0 then adjust this acceleration wth the acceleration due t0 gravity? When Ihe engine shuts ofl, which molion variable(s) changes and how does change? Calculation What is the maximum height that the rocket reaches? At what time atter launch will tne rocket retum to the ground? Queslion You drive into 120 meter long block Irom the Ielt end at = constant speed of 21 mls_ Alter some Ume. you brake with constant acceleralion 0l 3 msls: You want come (0 slop at Ine right end of the block: How much time (Irom when you enter Ihe block) should you wail belore braking? How far down the block (from the left end) d2 you travel before braking? Question You are rest at stop sign; There another stop sign that is 100 meters away: Your maximum acceleration is mists and You maximum braking acceleration misis How much time do you spend acceleraling? How much time do you spend braking? What is the tolal travel lime? Over how much distance do you accelerate? Over how much distance do you brake? What is the tolal travel distanco?

Explanation:

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Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron

TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

$d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m$

Next, you calculate the wavelength of the sound waves by using the following formula:

$\lambda=\frac{v_s}{f}$

vs: speed of sound = 343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

$\lambda=\frac{343m/s}{400Hz}=0.8575m$

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

$\Delta d=3.827m-2.10m=1.727m$

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

$\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2$

Then, there will be a constructive interference, and the sound who the observer hears is loud.

5 0

3 years ago

Ryan swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill on him:

nexus9112 [7]

Part 1

If water does not spill at the top point of the circular motion then for the minimum speed condition we can say normal force will be zero at the top position

$F_g = ma$