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Ksju [112]
2 years ago
13

descirbe the motion of the block oncw the rocket turned off. What would it take to get the block to acclereate again?

Physics
1 answer:
avanturin [10]2 years ago
3 0

Answer:

HW3 Motion (Ldimension _ obiecL acceleralions) Question rocket on the ground is launched with an acceleration of 40 m/s $ upward. seconds inlo the flight the engine shuts off: Assume there no air resistance. Preliminary questions The acceleraton of the rocket i5 40 mls/5. Do you have t0 then adjust this acceleration wth the acceleration due t0 gravity? When Ihe engine shuts ofl, which molion variable(s) changes and how does change? Calculation What is the maximum height that the rocket reaches? At what time atter launch will tne rocket retum to the ground? Queslion You drive into 120 meter long block Irom the Ielt end at = constant speed of 21 mls_ Alter some Ume. you brake with constant acceleralion 0l 3 msls: You want come (0 slop at Ine right end of the block: How much time (Irom when you enter Ihe block) should you wail belore braking? How far down the block (from the left end) d2 you travel before braking? Question You are rest at stop sign; There another stop sign that is 100 meters away: Your maximum acceleration is mists and You maximum braking acceleration misis How much time do you spend acceleraling? How much time do you spend braking? What is the tolal travel lime? Over how much distance do you accelerate? Over how much distance do you brake? What is the tolal travel distanco?

Explanation:

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WILL NAME THE BRAINLIEST! An airplane undergoes the following displacements: It first flies 72 km in a direction of 30° East of
nekit [7.7K]

Answer:

82.1 km

Explanation:

We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:

A_x = (72) sin 30^{\circ} =36.0 km\\A_y = (72) cos 30^{\circ} = 62.4 km

Vector B is 48 km south, so:

B_x = 0\\B_y = -48

Finally, vector C:

C_x = -(100) cos 30^{\circ} =-86.6 km\\C_y = (100) sin 30^{\circ} = 50.0 km

Now we add the components along each direction:

R_x = A_x + B_x + C_x = 36.0 + 0 +(-86.6)=-50.6 km\\R_y = A_y+B_y+C_y = 62.4+(-48)+50.0=64.6 km

So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is

R=\sqrt{R_x^2+R_y^2}=\sqrt{(-50.6)^2+(64.6)^2}=82.1 km

4 0
3 years ago
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kow [346]

Answer:

1.122 m/s

Explanation:

So usually a river with a speed of 1 meters per second can transport particle that weighs:

1^6 = 1 kg

If the particle is twice as massive as usual, then its weights would be 1 * 2 = 2kg

This means the river must be flowing at a speed of

2^{\frac{1}{6}} = 1.122 m/s

5 0
3 years ago
Why are negative ions usually larger than positive ions
irga5000 [103]
A negative ion is a atom that has an extra electron, but the same # of protons
4 0
3 years ago
Read 2 more answers
Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms
VARVARA [1.3K]
Good morning.

We have that:

\mathsf{V = a\cdot t} , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

\mathsf{V = \dfrac{F}{m} \cdot t}

We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

3 0
3 years ago
A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. in the water what angle
alexira [117]
<h3><u>Answer</u>;</h3>

= 22°

<h3><u>Explanation</u>;</h3>
  • According to Snell's law, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant. The constant value is called the refractive index of the second medium with respect to the first.
  • Therefore; Sin i/Sin r = η

In this case; Angle of incidence = 90° -60° =30°, angle of refraction =? and η = 1.33

Thus;

Sin 30 / Sin r = 1.33

Sin r = Sin 30°/1.33

       = 0.3759

r = Sin^-1 0.3759

   = 22.08

   <u>≈ 22°</u>

3 0
3 years ago
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