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3 years ago

A light microscope that has two or more lenses is called a ____________________ (compound, simple) microscope.

Chemistry

2 answers:

Sonbull [250]3 years ago

8 0

Compound microscope. uwu

Oduvanchick [21]3 years ago

3 0

That is called COMPOUND microscope....

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Calculate the heat (in calories) released when 115 g of CHCl3 changes from a liquid to a solid at

Alexandra [31]

Answer: 8855 Joules energy is released when 115 g of $CHCl_3$ changes from a liquid to a solid at its freezing point.

Explanation:

Latent heat of freezing is the amount of heat released to convert 1 mole of liquid to solid at atmospheric pressure.

Amount of heat released to freeze 1 gram of $CHCl_3$ = 77 J/g

Mass of $CHCl_3$ given = 115 gram

Heat released when 1 g of $CHCl_3$ is freezed = 77 J

Thus Heat released when 115 g of $CHCl_3$ is freezed = $\frac{77}{1}\times 115=8855J$

Thus 8855 Joules energy is released when 115 g of $CHCl_3$ changes from a liquid to a solid at its freezing point.

4 0

2 years ago

You wish to prepare a tape-casting slip containing 50 vol% Al2O3 and 50 vol% polyvinyl butyral (PVB) binder. If the density of A

belka [17]

Answer: The mass of PVB required to produce 1000 grams of tape is 213.4 grams

Explanation:

To calculate the mass of aluminium oxide, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ .......(1)

For $Al_2O_3$

We are given:

50% (v/v) of $Al_2O_3$

This means that 50 mL of aluminium oxide is present in 100 mL of tape

Calculating the mass of aluminium oxide by using equation 1:

Density of aluminium oxide = $3.98 g/cm^3$

Volume of aluminium oxide = $50mL=50cm^3$ (Conversion factor: $1mL=1cm^3$ )

Putting values in equation 1, we get:

$3.98g/cm^3=\frac{\text{Mass of aluminium oxide}}{50cm^3}\\\\\text{Mass of aluminium oxide}=(3.98g/cm^3\times 50cm^3)=199g$

Mass of aluminium oxide = 199 g

For PVB:

We are given:

50% (v/v) of PVB

This means that 50 mL of PVB is present in 100 mL of tape

Calculating the mass of PVB by using equation 1:

Density of PVB = $1.08 g/cm^3$

Volume of PVB = $50mL=50cm^3$

Putting values in equation 1, we get:

$1.08g/cm^3=\frac{\text{Mass of PVB}}{50cm^3}\\\\\text{Mass of PVB}=(1.08g/cm^3\times 50cm^3)=54g$

Mass of PVB = 54 g

Mass of tape = Mass of aluminium oxide + mass of PVB

Mass of tape = [199 + 54] g = 253 g

To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:

When 253 grams of tape is made, the mass of PVB required is 54 g

So, when 1000 grams of tape is made, the mass of PVB required will be = $\frac{54}{253}\times 1000=213.4g$

Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams

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2 years ago

For this exercise, you can simulate the described conditions by changing the values in the run experiment tool of the simulation

Furkat [3]

1) ideal gas law: p·V = n·R·T.
p - pressure of gas.
V -volume of gas.
n - amount of substance.
R - universal gas constant.
T - temperature of gas.
n₁ = 0,04 mol, V₁ = 0,06 l.
n₂ = 0,07 mol, V₂ = 0,06 · 0,07 ÷ 0,04 = 0,105 l.
2) V₁ = 0,06 l, T₁ = 240,00 K.
T₂ = 340,00 K, V₂ = 340 · 0,06 ÷ 240 = 0,05 l.

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2 years ago

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Hypothesis

notsponge [240]

Answer:

1) The problem is that you get a salty taste in our mouth when you drink orange juice after brushing our teeth.

Explanation:

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3 years ago

Adam is trying to identify a solid. He places a small amount of the substance in an acid solution and observes whether or not a

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