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yaroslaw [1]
4 years ago
6

What are the units of molality? A. mol/kg B. g/mol C. mol/L D. kg/mol

Chemistry
2 answers:
Vlad [161]4 years ago
6 0

Answer:

mol/L

Explanation:

mezya [45]4 years ago
4 0

Answer:

A. mol/kg

Explanation:

hope it helps .

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What is a synonym
Artyom0805 [142]

Answer:

conserved

Explanation:

3 0
3 years ago
Read 2 more answers
if 26.8g of copper (ll) chloride are dissolved in sufficient water to make 4.00 L of solution, what is the molarity of the solut
artcher [175]

Answer: Molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

Explanation:

Given: Mass of solute = 26.8 g

Volume = 4.00 L

Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{26.8 g}{134.45 g/mol}\\= 0.199 mol

Molarity is the number of moles of a substance divided by volume of solution in liter.

Therefore, molarity of given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.199 mol}{4.00 L}\\= 0.04975 M\\= 4.97 \times 10^{-2} M

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.

In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.

Thus, we can conclude that molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

4 0
3 years ago
A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of
Over [174]

Answer:

C

Explanation:

I got this question right on my test.

3 0
3 years ago
Chemical name of F3S2
natima [27]

Answers;

F3S2 Name: Iron Disulfide

Lead(II) nitrate formula: Pb(NO3)2

Silicon tetrafluoride formula: SiF4

4 0
2 years ago
Determine the specific heat of a material if a 35. Gram sample absorbed 96. Joules of energy as it was heated from 293 K to 313
podryga [215]

The specific heat of a material is 0.137 J/g°C.

<u>Explanation:</u>

The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.

Q = mcΔT

Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.

So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.

c = \frac{Q}{m\ \times\ delta\ T}

As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.

The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.

Similarly, the final temperature will be 313 - 273.15 = 39.85°C.

Then, ΔT = 39.85-19.85 = 20 °C

Then,

c = \frac{96}{35 \times 20} =\frac{96}{700}  = 0.137 J/g^{o}C

So, the specific heat of a material is 0.137 J/g°C.

6 0
3 years ago
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