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ololo11 [35]
3 years ago
11

How does the ramp produce mechanical advantage?

Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0
Makes it easier to move an object. It takes less force to move an object in an upward direction on an inclined plane than it does to lift the object straight up. ... However, the inclined plane reduces the force needed to do the work. I think u can use this answer
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Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,
aleksley [76]

Answer:

∆H=  <u>438 KJ/mol</u>

Explanation:

First, we have to find the <u>energy bond values</u> for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the <u>number of bonds</u>:

Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the <u>total energy for each bond</u>:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>

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I hope it helps!

7 0
3 years ago
A student dissolves powdered tea in water. How can the student separate the parts of the mixture?
mars1129 [50]

Answer:

The student can evaporate the liquid water.

Explanation:

The student only mixed water with the powdered tea. Therefore, if the water is evaporated from the mixture, the student will be left with the tea mixture only.

7 0
2 years ago
According to Graham’s law, the rate of effusion of a gas is inversely proportional to
VLD [36.1K]

C.  the square root of the mass of the particles.

<h3>Further explanation  </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.

So if both gases are at the same temperature and pressure, the above formula can apply

5 0
3 years ago
WILL CHOSE THE BRAINLIEST!!! NEED HELP FAST!!!
skelet666 [1.2K]
Its not always accurate because you dont know what they could have done to it before they try to sell it

3 0
3 years ago
What structure what structural feature of cells can allow molecules to flow directly from the inside of one cell to the inside o
Rufina [12.5K]
The answer is A. Plasmodesmata. It's a narrow pathway between cells.
3 0
3 years ago
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