The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.
<h3>What is a cathode ray?</h3>
A cathode ray is a tube that contains negatively charged electrode( that is the cathode) which emits electrons when heated at a low pressure.
The cathode ray was used by the scientist, J.J. Thomson to find the ratio of charge to mass (e/m) of the electrons.
Therefore, the scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.
Learn more about electrons here:
brainly.com/question/11316046
#SPJ1
Answer:
240 g/mol
Explanation:
We'll begin by writing the chemical formula of Disodium sulfide nonahydrate. This is illustrated below:
The molecular formula of disodium sulfide nonahydrate is Na₂S.9H₂O
Finally, we shall determine the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O. This can be obtained by adding the individual molar mass of the element present in the compound as illustrated below:
Molar mass of Na₂S.9H₂O = (23×2) + 32 + 9[(2×1) + 16]
= 46 + 32 + 9[2 + 16]
= 46 + 32 + 9[18]
= 46 + 32 + 162
= 240 g/mol
Thus, the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O is 240 g/mol
Answer:
27.025 g of H₂O
Explanation:
The Balance chemical equation is
2 H₂ + O₂ = 2 H₂O
Step 1: Calculate Limiting Reagent
Moles of H₂
Mole = 16 g / 2.02 g/mol = 7.937 mol
Moles of O₂
Mole = 24 g / 32.00 g/mol = 0.750 mol
Mole ratio of H₂ : O₂ is 2 : 1. Hence, 7.937 mol of H₂ will need 3.9685 mol of O₂. This means O₂ is limiting reagent.
Step 2: Calculate Moles of H₂O
0.750 mol of O₂ will produce 1.50 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.
Step 3: Calculate mass of H₂O
Mass = 1.50 mol × 18.02 g/mol = 27.025 g of H₂O
