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denis23 [38]
3 years ago
14

Rewrite the expression in the form 5^n (5^-8) (5^-10)

Mathematics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

5^-18

Step-by-step explanation:

Law of exponents bases the same add the exponents keep the base.

5^(-8+-10)=5^-18

oee [108]3 years ago
4 0

Answer:

Step-by-step explanation:

This problem is all about bases and exponents.  Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:

That's the simplification as long as you are "allowed" to leave the exponent as a negative number.

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Con la información que se encuentra a continuación completar la tabla sobre el valor posicional de los números.
joja [24]

Answer:

ok

Step-by-step explanation:

to hablando Espanol j

6 0
3 years ago
Mr Nersin likes to ride his bike. He rode for 1/2 hour. After a short rest, he rode 1/10 hour more. He traveled 4 miles in all.
vodomira [7]
The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
                                                                = (5 + 1)/10 hour
                                                                = 6/10 hour
                                                                = 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
                                                = 4/(3/5) miles/hour
                                                = (4 * 5)/3 miles/hour
                                               = 20/3 miles/hour
                                                = 6 2/3 miles/hour
                                                = 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
6 0
3 years ago
Read 2 more answers
Solve the inequality for x<br> 3^(6x+18)&lt;27^(3x)
Lera25 [3.4K]

Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}
  • Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
3 years ago
Read 2 more answers
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio
olga2289 [7]

Answer:

a) E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

b) E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

Step-by-step explanation:

We assume the following distribution given:

Y       0       1        2        3

P(Y) 0.60 0.25  0.10  0.05

Part a

We can find the expected value with this formula:

E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

Part b

If we want to find the expected value of 100 Y^2 we need to find the expected value of Y^2 and we have:

E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)

And replacing we got:

E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

4 0
3 years ago
Jenny’s home appraised for 550,000. Her asking price was 560,000 and the properties sold for 575,000. What were the new owners p
Alisiya [41]

Answer:

575,000

Step-by-step explanation:

5 0
3 years ago
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