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3 years ago

14

What is the answers pls need it before tomoz

1 answer:

QveST [7]3 years ago

5 0

Metals consist of giant structure of atoms arranged in a regular pattern. The electrons in the outer shell of metal atoms are shared , and are free to move throughout the structure. Therefore the structure is formed by positive charged metal ions held together by a 'sea' of delocalised.

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Please help *chemistry*

Daniel [21]

3 because I just did it

8 0

3 years ago

Diamond has a density of 3.513 g/cm³. The mass of diamonds is often measured in "carats," where 1 carat equals 0.200

Gennadij [26K]

The volume of a 1.86-carat diamond in cubic centimeters is 0.106 cm³

Given,

The density of a diamond is 3.513 g/cm³.

We have to find out the volume of a 1.86-carat diamond in cubic centimeters.

Convert the units of the diamond from carat to grams, we have:

(1.86 carats) x (0.200 g / 1 carat) = 0.372 g

The volume of the diamond is obtained by dividing the mass by the density, therefore using the formula, we get

v = m / d

v = 0.372 g / (3.51 g/cm³) = 0.1059 cm³

or, v = 0.106 cm³ (approx)

Therefore, the volume of a 1.86-carat diamond is approximately 0.106 cm³.

To learn more about the volume, visit: brainly.com/question/1578538

#SPJ9

4 0

1 year ago

An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder

seraphim [82]

Answer:

$\Delta H=-11897J$

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

$\Delta H=\Delta U+V\Delta P$

Whereas the change in the internal energy is computed by:

$\Delta U=nCv\Delta T$

So we compute the initial and final temperatures for one mole of the ideal gas:

$T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K }{n}$

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

$\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J$

Then, the volume-pressure product in Joules:

$V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J$

Finally, the change in the enthalpy for the process:

$\Delta H=-7140J-4757J\\\\\Delta H=-11897J$

Best regards.

7 0

3 years ago

Use the following balanced reaction to solve 1-3:

tino4ka555 [31]

Answer:

1.96g H2

Explanation:

P4 = 123.9g/mol

H2 = 2.02g/mol

$\frac{20g P_{4} }{1}$ * $\frac{1 mol P_{4} }{123.9g}$ * $\frac{6 mol H_{2} }{1 mol P_{4} }$ * $\frac{2.02g H_{2} }{1 mol H_{2} }$ = 1.96g H2

6 0

2 years ago

Most genetic mutations are repaired by____

Kay [80]

The correct Anwser is enzymes

7 0

3 years ago