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DiKsa [7]
2 years ago
7

HELP!!!!!!PLZ!!!!!ASAP!!!!!

Chemistry
1 answer:
AfilCa [17]2 years ago
8 0
It is an open series circuit and this is why:
 
its obvious its a series circuit because all the symbols are in a straight rectangle. 
its an open circuit because an open circuit has something that doesn't allow the electrons to flow all the way. and the thing blocking the electrons it the switch which is open, (off).

Hope this helped!! sorry its late!!
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Which reactant is unlikely to produce the indicated product upon strong heating?
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2-Methyl-4-oxo-pentanoic acid  is unlikely to produce 2-Methyl-3-butanone upon strong heating.

Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.

A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.

Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Full question :

Q.  Which reactant is unlikely to produce the indicated product upon strong heating?

  • A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
  • B) 2-Ethylpropanedioic acid Butanoic acid
  • C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
  • D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
  • E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone

Hence, option (D) is correct.

Learn more about carboxylic acid here : brainly.com/question/26855500

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