Answer:
The new temperature is 894 K or 621 °C
Explanation:
Step 1: Data given
Initial volume of the container = 2.000L
Initial temperature = 25.0 °C = 298 K
Volume increased to 6.00 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 2.00L
⇒with T1 = the initial temperature = 25 °C = 298 K
⇒with V2 = the increased volume 6.00 L
⇒with T2 = the new temperature
2.00 L / 298 K = 6.00 L / T2
T2 = 894 K = 621 °C
The new temperature is 894 K or 621 °C
This is a simple chemical change due to what it produces and how it is added together. Hope this helps.
Is this for science class I need more info to answer the following question
