Answer: from the Zn anode to the Cu cathode
Justification:
1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)
2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).
3) Then, you can already tell that electrons go from Zn to Cu.
4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.
So you get that the electrons flow from the anode (Zn) to the cathode (Cu).
Always oxidation occurs at the anode, and reduction occurs at the cathode.
Answer:
Nitrogen
Explanation:
Elements in period two includes lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.
According to periodic trends, the electro negativity values are expected to increase across the period up to fluorine. Hence, as we go right wards, we encounter elements with higher electronegative values.
While lithium has an electronegative value of 1 , the electronegative value of element nitrogen is thrrr times this which is equal to three
Answer:
it's a chemistry change
Explanation:
this is because heat is causing permanent changes and can no longer be changed back to its original atate
Answer: All of them are true
The order of the answers are as follows:
B
C
D
A
