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GREYUIT [131]
2 years ago
8

According to the ideal gas law for a fixed amount of gas, if the _____ is constant, then when the ________ increases the volume

should ________.
a) temperature, pressure, increase
b) pressure, temperature, decrease
c) pressure, volume, decrease
d) none of the above
Chemistry
1 answer:
BARSIC [14]2 years ago
5 0

Answer:

D. none of the above

Explanation:

A. is wrong because pressure and volume have an inverse relationship. When one increases the other decreases, this is not an option.

B. is wrong because temperature and volume have a proportional relationship. One one goes up, the other goes up or vice versa.

C. is wrong because volume cannot increase the then decrease at the same time.

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AleksAgata [21]

Answer:

17.2 moles of Iron are required

Explanation:

Based on the chemical reaction:

2Fe + 3S → Fe₂S₃

<em>2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide</em>

<em />

Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:

8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =

<h3>17.2 moles of Iron are required</h3>
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Integrated rate law for second order unimolecular irreversible
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Answer:

The rate law for second order unimolecular irreversible reaction is

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

Explanation:

A second order unimolecular irreversible reaction is

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Thus the rate of the reaction is

v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}

rearranging the ecuation

-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}

Integrating between times 0 to <em>t </em>and between the concentrations of [A]_{0} to <em>[A].</em>

\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}

Solving the integral

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

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Nuetrik [128]

Answer:

Nuclear

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Geo-Thermal

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Explanation:

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