When we have this balanced equation for a reaction:
Fe(OH)2(s) ↔ Fe+2 + 2OH-
when Fe(OH)2 give 1 mole of Fe+2 & 2 mol of OH-
so we can assume [Fe+2] = X and [OH-] = 2 X
when Ksp = [Fe+2][OH-]^2
and have Ksp = 4.87x10^-17
[Fe+2]= X
[OH-] = 2X
so by substitution
4.87x10^-17 = X*(2X)^2
∴X^3 = 4.8x10^-17 / 4
∴the molar solubility X = 2.3x10^-6 M
What are the statements ?
Answer: B. The anion affects the color of the solution more than the intensity of the color.
Explanation:
An ionic bond is gotten when an electron is transferred from a metal atom to a non-metal one. It should be noted that the ionic bonds simply has an anion and a cation.
An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.
The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.
