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True [87]
2 years ago
10

9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A l

ow-boiling liquid was obtained instead of ethylene. What was the liquid, and how might the reaction conditions be changed to give ethylene
Chemistry
1 answer:
Arte-miy333 [17]2 years ago
8 0

We have that the the liquid is

  • C_2H_5OH (ethanol
  • And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

  • A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
  • A low-boiling liquid was obtained instead of ethylene.
  • What was the liquid, and how might the reaction conditions be changed to give ethylene

<h3>Ethylene formation</h3>

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

  • C_2H_5OH (ethanol

For more information on Ethylene visit

brainly.com/question/20117360

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