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fgiga [73]
2 years ago
10

How many electrons are there in 2 g of H2

Chemistry
1 answer:
KiRa [710]2 years ago
4 0

Answer:

6.02 x 10²³ electrons

Explanation:

Given parameters:

Mass of H₂  = 2g

Unknown:

Number of electrons = ?

Solution:

To find the number of electrons, we must determine the number of moles of H₂ first.

 Number of moles  = \frac{mass}{molar mass}  

  Molar mass of H₂   = 2(1)  = 2g/mol

Number of moles  = \frac{2}{2}   = 1mol  

1 mole of a substance contains 6.02 x 10²³ particles

the particles can be protons, neutrons, electrons

So,

  2g of H₂ will contain 6.02 x 10²³ electrons.

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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq) , as desc
vlada-n [284]

Answer:

0.87g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

Step 2:

Data obtained from the question. This includes the following:

Volume (V) of Cl2 obtained = 235mL

Temperature (T) = 25°C

Pressure (P) = 805 Torr

Step 3:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 235mL = 235/1000 = 0.235L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 25°C

Temperature (Kelvin) = 25°C + 273 = 298K

For Pressure:

760 Torr = 1 atm

Therefore, 805 Torr = 805/760 = 1.06 atm

Step 4:

Determination of the number of mole of Cl2 produced. This is illustrated below:

The number of mole (n) of Cl2 produced can be obtained by using the ideal gas equation as follow:

PV = nRT

Volume (V) = 0.235L

Temperature (T) = 298k

Pressure (P) = 1.06 atm

Gas constant (R) = 0.082atm.L/Kmol

Number of mole (n)

PV = nRT

Divide both side by RT

n = PV /RT

n = (1.06 x 0.235)/(0.082 x 298)

n = 0.01 mole

Therefore 0.01 mole of Cl2 is produced from the reaction.

Step 5:

Determination of the number of mole MnO2 that produce 0.01 mole of Cl2. This is illustrated below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

From the balanced equation above,

1 mole of MnO2 produced 1 mole of Cl2.

Therefore, it will take 0.01 mole to MnO2 to also produce 0.01 mole of Cl2.

Step 6:

Converting 0.01 mole of MnO2 to grams.

This is illustrated below:

Number of mole MnO2 = 0.01 mole

Molar Mass of MnO2 = 55 + (2x16) = 87g/mol

Mass of MnO2 =?

Mass = number of mole x molar Mass

Mass of MnO2 = 0.01 x 87

Mass of MnO2 = 0.87g

Therefore, 0.87g of MnO2 is needed for the reaction.

8 0
3 years ago
Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment t
AleksandrR [38]

Answer:

Explanation:

  1. 7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper.  
  2. Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide.  
  3. Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it.  
  4. so a 25mL sample of algaecide must have around 1.75g of copper.
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Plz help me with this problem
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Answer:

4feet

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Because when he moves he only goes 4 miles every time I

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The area is 60.2, to find area it's length times width.

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Answer:

Mutualism

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