A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground.
1 answer:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The electric field at that point is
Explanation:
From the question we are told that
The radius of the inner circle is
The radius of the outer circle is
The charge on the spherical shell
The magnitude of the point charge at the center is
The position we are considering is x = 0.60 m from the center
Generally the electric field at the distance x = 0.60 m from the center is mathematically represented as
substituting values
where k is the coulomb constant with value
substituting values
