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MakcuM [25]
3 years ago
11

Study the free body diagram above. Which scenario below can best be described with this free body diagram? A. a cup is at rest o

n a table. B. a car coasts down a hill. C. a child drops a penny from the top of a building. Neglect air resistance. D. a bartender slides a glass of beer to a patron at the end of a bar. Neglect air resistance.

Physics
1 answer:
vekshin13 years ago
5 0

Answer: D

Explanation:

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0.10-kilogram model rocket’s engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75
UkoKoshka [18]

Answer:

8.0 N

Explanation:

Force: This can be defined as the mass of a body and its acceleration. The S.I unit of Force is Newton (N).

Mathematically, Fore is expressed as

F = ma ........................... equation 1

Where F = force, m = mass, a = acceleration.

and

I = mΔv

Δv = I/m ............................ Equation 2

Where I = impulse, m = mass, Δv = change in velocity

Given: I = 6.0 Newton-seconds, m = 0.1 kilogram.

Substituting into equation 2

Δv = 6.0/0.1

Δv = 60 m/s.

But

a = Δv/t

where t = time = 0.75 seconds.

a = 60/0.75

a = 80 m/s²

Substitute the values of a and m into equation 1.

F = 0.1(80)

F = 8.0 N.

Thus the average force produced = 8.0 N

6 0
2 years ago
Identify the areas on the image where the force of repulsion is the least.​
aalyn [17]

Answer:

The central blue square in between the lower pair of magnet has the least force of repulsion.

Explanation:

We can explain this using the dual nature of magnets.

Each magnet must have two poles namely:

-North pole

-South pole

We assume that the magnetic lines of forces enters from south pole and leaves from the north pole.

When brought together, like poles repel each other while opposite poles attract each other.

In the picture, the lower two magnets have opposite poles facing each other, hence the force of repulsion is minimum there and the force of attraction is maximum.

4 0
3 years ago
Read 2 more answers
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel
mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

\vec v_{ra} = 12 m/s North

so it will be

Let North direction is along Y axis and East direction is along X axis

\vec v_{ra} = 12\hat j

also it is given that speed of air is 6.7 m/s relative to ground

\vec v_a = 6.7 \hat i

now as we know by the concept of relative motion

\vec v_{ab} = \vec v_a - \vec v_b

\vec v_{ra} = \vec v_r  - \vec v_a

now by rearranging the terms

\vec v_r = \vec v_{ra} + \vec v_a

\vec v_r = 12 \hat j + 6.7 \hat i

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

v_r = \sqrt{12^2 + 6.7^2}

v_r = 13.7 m/s

so the net speed of Robin with respect to ground will be 13.7 m/s

7 0
3 years ago
¿Cuál es la constante de proporcionalidad entre Y y X2?
djyliett [7]
This isn’t anything related to physics dude
5 0
3 years ago
The 225-N force is exerted on the crate towards the north and the 165-N is exerted toward the East what's the magnitude and dire
Rudik [331]

Answer:

≅279.02 N, 36° 15' from North to East

Explanation:

You can the theory of triangle of forces to find the answer.

Two forces are acting perpendicular to each other so use Pythagoras theorem to find the magnitude of the resultant  force(x).

x² = 225² + 165²

x = 279.02 N

To find the direction use the same force triangle,

Workings are in the attachment,

Download pdf
6 0
3 years ago
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