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3 years ago

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Physics

2 answers:

mixer [17]3 years ago

6 0

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

$W = F \times d$

Where, W = work

F = force

d = distance

Put the value into the formula of work

$W= 1500\times40$

$W = 60000\ Pounds-feet$

Power:

The power is equal to the work done divided by time.

The power is defined as,

$P = \dfrac{W}{t}$

Where, P = power

W = work

t = time

Put the value into the formula of power

$P = \dfrac{60000}{20}$

$P=3000\ Pounds-feet/s$

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

svlad2 [7]3 years ago

4 0

Work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20

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Answer:

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To solve this problem it is necessary to apply the concepts related to mutual inductance in a solenoid.

This definition is described in the following equation as,

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How to solve number 10

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The 'formulas' to use are just the definitions of 'power' and 'work':

Power = (work done) / (time to do the work)

and

Work = (force) x (distance) .

Combine these into one. Take the definition of 'Work', and write it in place of 'work' in the definition of power.

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From the sheet, we know the power, the distance, and the time. So we can use this one formula to find the force.

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Multiply each side by (time): (Power) x (time) = (force) x (distance)

Divide each side by (distance): Force = (power x time) / (distance).

Look how neat, clean, and simple that is !

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Is that awesome or what !

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