Question

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Answer 1

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

$W = F \times d$

Where, W = work

F = force

d = distance

Put the value into the formula of work

$W= 1500\times40$

$W = 60000\ Pounds-feet$

Power:

The power is equal to the work done divided by time.

The power is defined as,

$P = \dfrac{W}{t}$

Where, P = power

W = work

t = time

Put the value into the formula of power

$P = \dfrac{60000}{20}$

$P=3000\ Pounds-feet/s$

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Answer 2

Work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20