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ASHA 777 [7]
3 years ago
11

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Physics
2 answers:
mixer [17]3 years ago
6 0

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

W = F \times d

Where, W = work

F = force

d = distance

Put the value into the formula of work

W= 1500\times40

W = 60000\ Pounds-feet

Power:

The power is equal to the work done divided by time.

The power is defined as,

P = \dfrac{W}{t}

Where, P = power

W = work

t = time

Put the value into the formula of power

P = \dfrac{60000}{20}

P=3000\ Pounds-feet/s

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

svlad2 [7]3 years ago
4 0
Work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20
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Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

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3 years ago
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Objects dropped straight or thrown horizontally from the same height
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3 years ago
All rules to find work in changing force in physics ​
saw5 [17]

Answer:

FORCE - rate of change of momentum, ie its changing velocity [change in velocity is of more concern] NEWTON

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7 0
2 years ago
011 10.0 points
Sedbober [7]
<h2>The temperature of the air is 66.8° C</h2>

Explanation:

From the Newton's  velocity of sound relationship , the velocity of sound is directly proportional to the square root of temperature .

In this case The velocity of sound = frequency x wavelength

= 798 x 0.48 = 383 m/sec

Suppose the temperature at this time = T K

Thus 383 ∝ \sqrt{T}                       I

The velocity of sound is 329 m/s at 273 K ( given )

Thus 329 ∝ \sqrt{273}                   II

Dividing I by II , we have

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or \frac{T}{273} = 1.25

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