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3 years ago

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Physics

2 answers:

mixer [17]3 years ago

6 0

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

$W = F \times d$

Where, W = work

F = force

d = distance

Put the value into the formula of work

$W= 1500\times40$

$W = 60000\ Pounds-feet$

Power:

The power is equal to the work done divided by time.

The power is defined as,

$P = \dfrac{W}{t}$

Where, P = power

W = work

t = time

Put the value into the formula of power

$P = \dfrac{60000}{20}$

$P=3000\ Pounds-feet/s$

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

svlad2 [7]3 years ago

4 0

Work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20

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3 years ago

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The answer to your question is m₂ = 38.5 kg

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