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arlik [135]
2 years ago
10

A positive rod is placed to the left of sphere A ,and the spheres are separated

Physics
2 answers:
bekas [8.4K]2 years ago
8 0

BSphere A is negative and sphere B is positive because electrons from sphere B are attracted to the rod and move to sphere A.

Romashka [77]2 years ago
5 0
When a positive rod is placed to the right of sphere B, and the spheres are separated, the reason behind this is the same charge on the sphere as the rod i.e. the right of the sphere also had a positive charge. Thus, the same positive charges could not reside on the right side surface of the sphere due to which it separation happens.

Read more on Brainly.com - brainly.com/question/4135790#readmore
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A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s.
ELEN [110]
Momentum = mass x velocity

Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s

After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
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Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s

Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
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= 91.73 J

Total kinetic energy lost during collision
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2 years ago
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A book is moved once around the edge of a tabletop with dimensions 1.75 m à 2.25 m. If the book ends up at its initial position,
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Explanation:

The dimension of the book is 1.75 m × 2.25 m. If the book ends up at its initial position. The displacement of the book is equal to zero as the object reaches to its initial position.

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Total displacement of the book is equal to its perimeter. It is given by :

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The average speed of an object is given by :

v=\dfrac{d}{t}

v=\dfrac{8\ m}{23\ s}

v = 0.347 m/s

So, the average speed of the book is 0.347 m/s. Hence, this is the required solution.

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