This type of wave is a transverse wave, or an S wave (secondary wave)
Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector,
= 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ =
× cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R
=
× sin(θ)
∴ R
= 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em>
<em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R
·j
∴
≈ -16.07·i + 19.15j)
Answer:2.103 m/s
Explanation:
Given
mass of sports car 
mass of SUV 
Suppose u is the velocity if sports car before collision
Conserving momentum we get



After collision the combined mass drag 2.8 m and finally stops
From work energy theorem work done by friction is equal to change in kinetic energy of the combined mass system

where 




Initial velocity 

Hi!
The answer B. a flow of electric charge
Hope this helps !
800 J is the work done by the student to lift the box of books.
Answer:
Explanation:
Work done is the measure of force required to move an object from one position to another. So it can be determined by the product of force and displacement of the object.
Work done to lift the box of books = Force acting on the box × Distance the box is lifted.
So here the displacement or the distance of the box being lifted is given as 4 m and the force acting on the box is given as 200 N.
Then, work done = 200 × 4 = 800 J.
So 800 J is the work done by the student to lift the box of books.