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Daniel [21]
3 years ago
6

Write a script for a 5-min mock debate between Edison and Tesla, in which each tries to convince the audience that he was the mo

re influential inventor. To support their arguments, Edison and Tesla should provide multiple examples of the everyday devices that are the result of their inventions.
Physics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

edieson and atela script once upon a time there was the name is a copy paste and the you can come by the office and I have a car so we can do it tomorrow if I will be working from the gathered that was a week if we were in w

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complete the following equation that represents the complete combustion of hexane in a car engine.C6H14 + O2
mina [271]

The balanced combustion reaction for butane is;

2C4H10 + 13O2 → 8CO2 + 10H2O

Molar mass of water = 18.02 g/mol

Molar mass of oxygen = 32 g/mol

 

2.46g H2O(1 mol H2O/18.02g)(13 mol O2/10 mol H2O)(32g O2/1 mol O2) = 5.68g O2

5 0
3 years ago
A ball has mass of 140g. what is the force to accelerate the ball at 25m/s
Fittoniya [83]

We know, F = m * a

Here, m = 140 g = 0.140 Kg

a = 25 m/s2

It would be: F = 0.140 * 25 = 3.5 N

So your answer would be 3.5N


6 0
3 years ago
Read 2 more answers
12
Helen [10]

Answer:

wavelength decreases and frequency increase

Explanation:

the higher the wavelength the smaller the frequency , the smaller the wavelength the higher the frequency

5 0
3 years ago
A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART
Gennadij [26K]

Answer:

\nu =1166\times 10^{20}Hz  

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron =9.11\times 10^{-31}kg

So mass of SPARTYON =945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg

Speed of light c=3\times 10^8m/sec

According to Einstein equation energy is given by

E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j

Now according to planks's rule

Energy is given by

E=h\nu , here h is plank's constant h=6.6\times 10^{-34}

So 77480.55\times 10^{-15}=6.6\times 10^{-34}\nu

\nu =1166\times 10^{20}Hz  

3 0
3 years ago
While investigating Kirchhoff's Laws, you begin observing a blackbody, such as a star, from Earth using advanced technology that
Ksenya-84 [330]

Answer:

the second time there is a gas between you and the star,

Explanation:

When you observe the star for the first time you do not have a given between you and the star, therefore you observe the emission spectrum of the same that is formed by lines of different intensity and position that indicate the type and percentage of the atoms that make up the star.

 When you observe the same phenomenon for the second time there is a gas between you and the star, this gas absorbs the wavelengths of the star that has the same energies and the atomisms and molecular gas, therefore these lines are not observed by seeing a series of dark bands,

The information obtained from the two spectra is the same, the type of atoms that make up the star

7 0
3 years ago
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