Answer:
magnitude of the velocity
Explanation:
Answer:
a) θ₁ = 23.14 °
, b) θ₂ = 51.81 °
Explanation:
An address network is described by the expression
d sin θ = m λ
Where is the distance between lines, λ is the wavelength and m is the order of the spectrum
The distance between one lines, we can find used a rule of proportions
d = 1/600
d = 1.67 10⁻³ mm
d = 1-67 10⁻³ m
Let's calculate the angle
sin θ = m λ / d
θ = sin⁻¹ (m λ / d)
First order
θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)
θ₁ = sin⁻¹ (3.93 10⁻¹)
θ₁ = 23.14 °
Second order
θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)
θ₂ = sin⁻¹ (0.786)
θ₂ = 51.81 °
Answer:
88.2 N
Explanation:
Datos
Lcubo = 10 cm = 0.1 m
Vcubo = Vfluido desalojado= 0.1 m x 0.1 m x 0.1 m = 10-3 m
mcubo = 10 kg
dfluido = 1000 kg/m3
g = 9.8 m/s2
Sabemos que el peso aparente de un cuerpo que se sumerge en un fluido es:
Paparente=Preal−Pfluido
Teniendo en cuenta que:
Preal = mcubo⋅gPfluido=E= dfluido⋅Vfluido⋅g
Como el cuerpo se sumerge completamente en el fluido, el volumen de fluido desalojado es exactamente el volumen del cubo. Por lo tanto si sustituimos los datos que nos proporcionan en el enunciado en la primera ecuación:
Paparente=mcubo⋅g−dfluido⋅Vfluido⋅g ⇒Paparente=10 kg ⋅9.8 m/s2 − 1000 kg/m3 ⋅10−3 m ⋅9.8 m/s2 ⇒Paparente = 88.2 N
Explanation:
003 (part 1 of 2)
Pressure is force divided by area.
P = F / A
P = (117 kg × 9.8 m/s²) / (2 × (0.05 m)²)
P = 229,320 Pa
003 (part 2 of 2)
There are approximately 6895 Pa in 1 psi.
P = 229,320 Pa × (1 psi / 6895 Pa)
P = 33.3 psi
004 (part 1 of 2)
Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).
Impulse = change in momentum
F Δt = m Δv
F (36 s) = (300 × 0.003 kg) (5.2 sin 57° m/s − (-5.2 sin 57° m/s))
F = 0.218 N
004 (part 2 of 2)
Pressure is force over area.
P = F / A
P = 0.218 N / 0.712 m²
P = 0.306 N/m²
