Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
Answer: 0.00068 N
Explanation: Universal gravitational constant=6.674 *10^(-11)
Force=Gm1m2/(r^2)
Force= 6.67*25000*40000*10^(-11)/(10^2)
Force=0.00068 N
Because cold air tends to more dense, and it's therefore heavier, and it sinks.
Hot air though is hot with no density so it's light and rises.
<span>¿Qué estás pidiendo en esta situación. Hay entornos de diferencia de los animales. Algunos viven en entornos de tundra, otra veraniega en vivo, ambientes cálidos.</span>
Answer:
The tension force in the supporting cables is 7245N
Explanation:
There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:
We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:
The tension force F in the supporting cables is 7245N
