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Kazeer [188]
3 years ago
9

Please answer this question , I’m not solve

Physics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

makinig ka kasi sa titser mo tas intindihin mo bobo

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A person of mass 75 kg stands at the center of a rotating merry-go-round platform of radius 3.3 m and moment of inertia
vivado [14]

Answer:

(a) 0.426 rad/s

(b) Before 296.225 J and After 148.5 J

Explanation:

At the center of merry-go-round, the person's weight is 75 Kg with moment of inertia of 820 kgm2 and the initial angular velocity is 0.85 rad/s

At the edge, the new angular velocity gained depends on the new moment of inertia

Here, the final moment of inertia is given by Initial moment of inertia + MR^{2} where M is the mass and R is the radius of merry-go-round

Final moment of inertia=820+(75*3.3^{2})=1636.75

From the law of conservation of angular momentum as torque is zero

I_i\times\omega_1=I_f\times\omega_2  and making \omega_2 the subject then

\omega_2=\frac {I_i\times\omega}{I_f}

where I_i and I_f are initial and final moment of inertia, \omega_1 and \omega_2 are initial and final angular velocity.

Substituting the provided values

\omega_2=\frac {0.85\times 820}{1636.75}=0.425843898\approx 0.426 rad/s

(b)

Initial rotational kinetic energy is given by

0.5I_i\times \omega_1^{2}

KE_i=0.5\times 820\times 0.85^{2}=296.225 J

The final rotational kinetic energy is given by

0.5I_f\times \omega_2^{2}

KE_i=0.5\times 1636.75\times 0.426^{2}\approx 148.5 J

7 0
3 years ago
Can somebody please help me? PLEASE
ale4655 [162]

Answer:

The 1st Answer

Explanation:

Because kinetic energy is the energy which a body possesses by virtue of being in motion. So if the velocity of the object (cannonball in this case) decreases than so would the kinetic energy

6 0
3 years ago
What is acceleration?​
jasenka [17]

Answer:

the rate of change of velocity per unit of time.

3 0
3 years ago
Read 2 more answers
Consider an electron that is 10-10 m from an alpha particle (9 = 3.2 x 10-19 C). (Enter the magnitudes.) (a) What is the electri
Studentka2010 [4]

Answer:

a)E=2.88*10^{11}N/C

b)E=1.44*10^{11}N/C

c)F=4.61*10^{-8}N

Explanation:

We use the definition of a electric field produced by a point charge:

E=k*q/r^2

<u>a)Electric Field  due to the alpha particle:</u>

E=k*q_{alpha}/r^2=9*10^9*3.2*10^{-19}/(10^{-10})^2=2.88*10^{11}N/C

<u>b)Electric Field  due to electron:</u>

E=k*q_{electron}/r^2=9*10^9*1.6*10^{-19}/(10^{-10})^2=1.44*10^{11}N/C

<u>c)Electric Force on the alpha particle, on the electron:</u>

The alpha particle and electron feel the same force but with opposite direction:

F=k*q_{electron}*q_{alpha}/r^2=9*10^9*1.6*10^{-19}*3.2*10^{-19}/(10^{-10})^2=4.61*10^{-8}N

4 0
3 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
shtirl [24]
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
3 0
3 years ago
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