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Neko [114]
4 years ago
10

During which of the following chemical changes does a precipitate form?

Physics
2 answers:
babymother [125]4 years ago
5 0

Answer is B.........

kolbaska11 [484]4 years ago
3 0

Answer: Option (B) is the correct answer.

Explanation:

A solid which is not soluble and has formed from the liquid solution is known as a precipitate.

For example, when lemon juice is added to milk then it results in the formation of paneer (cheese) that is insoluble.

Hence, we can conclude that during the addition of lemon juice into milk will bring a chemical change by forming a precipitate.

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For a particle undergoing free-fall acceleration, the acceleration vs. time graph is
Sergeeva-Olga [200]
A straight line of y = 9.8
5 0
4 years ago
A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a v
bulgar [2K]

Answer:

  F = 1908 N

Explanation:

GIVEN,

Incident water stream has a velocity = U = +18.0 m/s,

Exiting water stream has a velocity = V = -18.0 m/s.

Mass of water per sec : M / t = 53 kg /s

Change in velocity   d v =18 m / s – ( -18 m / s)  

                                       = 36 m / s  

Magnitude of the average force exerted on the water by the blade  

  F = ( M / t ) x dv

      =( 53 kg /s ) x ( 36 m/s )

  F = 1908 N

3 0
3 years ago
If a total 50 J of work are done on an object, it's energy...
babymother [125]

Answer:

0.0119502868 kilocalorie

Explanation:

8 0
3 years ago
suppose the spring in the sample problem is replaced with a spring that stretches 36 cm from its equilibrium position
amm1812

The gravitational force is acting downward as the spring is held vertically. Therefore, spring is stretched downward and the force is directly proportional to the stretched distance. The product of the mass and the gravitational acceleration gives gravitational force.

3 0
3 years ago
A 0.0208 m diameter coin rolls up a 18.0◦ inclined plane. The coin starts with an initial angular speed of 56.0 rad/s and rolls
anastassius [24]

Answer:

h = 0.0259 m

Explanation:

given,

diameter of the cone = 0.0208 m

                     radius,r = 0.0104 m

angle of inclination,θ = 18°

initial angular velocity, ω_i = 56 rad/s

final angular velocity ,ω_f = 0 rad/s

height, h = ?

Rotational kinetic energy

KE_r = \dfrac{1}{2}I\omega^2

Moment of inertia of coin

I = \dfrac{1}{2}MR^2

so,

KE_r = \dfrac{1}{4}MR^2\omega^2

Transnational Kinetic energy

KE_t = \dfrac{1}{2}Mv^2

v = r ω

KE_t = \dfrac{1}{2}MR^2\omega^2

now,

using conservation energy

Kinetic energy of the coin is converted into the potential energy  

KE_r + KE_t = PE

\dfrac{1}{4}MR^2\omega^2 + \dfrac{1}{2}MR^2\omega^2 = Mgh

\dfrac{3}{4}R^2\omega^2=gh

\dfrac{3}{4}\times 0.0104^2\times 56^2=9.8\times h

h = 0.0259 m

Vertical height gain by the coin is equal to 0.0259 m

7 0
4 years ago
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