Before the engines fail
, the rocket's horizontal and vertical position in the air are


and its velocity vector has components


After
, its position is


and the rocket's velocity vector has horizontal and vertical components


After the engine failure
, the rocket is in freefall and its position is given by


and its velocity vector's components are


where we take
.
a. The maximum altitude occurs at the point during which
:

At this point, the rocket has an altitude of

b. The rocket will eventually fall to the ground at some point after its engines fail. We solve
for
, then add 3 seconds to this time:

So the rocket stays in the air for a total of
.
c. After the engine failure, the rocket traveled for about 34.6 seconds, so we evalute
for this time
:

Answer:
ω = 1.83 rad/s clockwise
Explanation:
We are given:
I1 = 3.0kg.m2
ω1 = -5.4rad/s (clockwise being negative)
I2 = 1.3kg.m2
ω2 = 6.4rad/s (counterclockwise being positive)
By conservation of the momentum:
I1 * ω1 + I2 * ω2 = (I1 + I2) * ω
Solving for ω:

Since it is negative, the direction is clockwise.
Answer:
Radius=15.773 m
Explanation:
Given data
v=29.5 km/h=8.2 m/s
μs=0.435
To find
Radius R
Solution
The acceleration is a centripetal acceleration which is experienced by the bicycle given by

This acceleration is only due to static force which given as

The maximum value of the static force is given as

where
FN is normal force equal to mass*gravity
Therefore when the car is on the verge of sliding

Therefore the minimum radius should be found by the bicycle move without sliding
So

Answer:
D
Explanation:
From the formula of coulombs law F = Kq1q2/square of r, we can say the electric force is indirectly related to square of r