Answer:
Vapor pressure of solution is 78.2 Torr
Explanation:
This is solved by vapor pressure lowering:
ΔP = P° . Xm . i
Vapor pressure of pure solvent (P°) - vapor pressure of solution = P° . Xm . i
NaCl → Na⁺ + Cl⁻ i = 2
Let's determine the Xm (mole fraction) These are the moles of solute / total moles.
Total moles = moles of solvent + moles of solute
Total moles = 0.897 mol + 0.182 mol → 1.079 mol
0.182 / 1.079 = 0.168
Now we replace on the main formula:
118.1° Torr - P' = 118.1° Torr . 0.168 . 2
P' = - (118.1° Torr . 0.168 . 2 - 118.1 Torr)
P' = 78.2 Torr
Explanation:
I want to say either a or b because primary is based on the habitat and whatever happens after while secondary is the result to disturbance causing an effect
Answer:
Explanation:
A solid, at a given temperature, has a definite volume
and shape which may be affected by changes in
temperature. Solids usually increase slightly in size
when heated (expansion) and usually
decrease in size if cooled (contraction).A liquid, at a given temperature, has a
fixed volume and will take up the shape of any
container into which it is poured. Like a solid, a
liquid’s volume is slightly affected by changes in
temperature.
A gas, at a given temperature, has neither a definite
shape nor a definite volume. It will take up the shape
of any container into which it is placed and will
spread out evenly within it. Unlike those of solids
and liquids, the volumes of gases are affected quite
markedly by changes in temperature.
Answer:
b. .28 M KCI
Explanation:
Use the dilution formula.
C₁V₁ = C₂V₂
C₂ = C₁V₁/V₂
C₂ = 1.6*0.175 / 1.0
C₂ = 0.28
Answer:
ΔG = -49.64 KJ/mol
Explanation:
The actual free energy change of the reaction under the given conditions, ΔG is given by the formula below;
ΔG = ΔG'° + RT ln([ADP][HPO₂⁴⁻] / [ATP])
where ΔG'° = -30.5 KJ/mol; R = 8.315 J/mol.K; T = 37°C = 310 K; [ADP] = 5.0 mM = 0.005 M; [HPO₂⁴⁻] = 0.60 mM = 0.0006 M; [ATP] = 5.0 mM = 0.005 M
ΔG = -30.5 KJ/mol + (8.315 J/mol.K)(310 K) ln {(0.005)(0.0006)/(0.005)}
ΔG = -30.5 KJ/mol + (2.58 KJ/mol * -7.4186)
ΔG = -30.5 KJ/mol - 19.14 KJ/mol
ΔG = -49.64 KJ/mol
