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Mariulka [41]
3 years ago
14

The amount of solid NaOH was doubled. Explain how the results of ∆T and ∆Hsoln would differ from the original experiment. Origin

al Question: An aqueous solution is made using 5.25 g of solid NaOH in 75.0 g of water initially at 22.39 °C in a sealed calorimeter. Specific heat=4.184 J/g and ∆T=17
Chemistry
1 answer:
topjm [15]3 years ago
4 0
This is so confusing
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The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
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Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al
hodyreva [135]

Answer:

0.384\ \text{L}

Explanation:

P_1 = Initial pressure = 931 torr = 931\times \dfrac{101.325}{760}=124.12\ \text{kPa}

P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

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2 years ago
PLEASE HELP<br><br> is this a chemical or physical change???
skad [1K]

Answer:

Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.

Explanation:

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