Question

A sharp edged orifice with a 60 mm diameter opening in the vertical side of a large tank discharges under a head of 6 m. If the coefficient of contraction is 0.68 and the coefficient of velocity is 0.92, what is the discharge?

Answer 1

Answer:

The discharge rate is $Q = 0.0192 \ m^3 /s$

Explanation:

From the question we are told that

   The  diameter is  $d = 60 \ mm = 0.06 \ m$

    The  head is  $h = 6 \ m$

     The  coefficient of contraction is  $Cc = 0.68$

     The  coefficient of  velocity is  $Cv = 0.92$

The radius is mathematically evaluated as

         $r = \frac{d}{2}$

substituting values

        $r = \frac{ 0.06 }{2}$

        $r = 0.03 \ m$

The  area is mathematically represented as

      $A = \pi r^2$

substituting values

      $A = 3.142 * (0.03)^2$

      $A = 0.00283 \ m^2$

 The  discharge rate is mathematically represented as

        $Q = Cv *Cc * A * \sqrt{ 2 * g * h}$

substituting values

       $Q = 0.68 * 0.92* 0.00283 * \sqrt{ 2 * 9.8 * 6}$

       $Q = 0.0192 \ m^3 /s$