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charle [14.2K]
2 years ago
6

When a capacitor, in RC circuit, is fully charged, the current through the resistor is Select one: zero if it is the only capaci

tor, but maximum if there is another capacitor in series with it. At its maximum value. Greater than the current in a resistor that is farther from the battery than the capacitor. Zero. Equal to the current in a resistive circuit in parallel with the capacitor circuit.
Physics
1 answer:
garri49 [273]2 years ago
7 0

Answer:

The correct option is "Zero". A further explanation is given below.

Explanation:

As we know,

The capacitor is given by:

⇒ Q=C\times V

Rate of change with respect to the time will be:

⇒ \frac{dQ}{dt}=C\times \frac{dV}{dt}

Now,

It is mentioned in the question that the capacitor is completely charged, then

⇒ \frac{dV}{dt}=0

i.e.,

⇒ \frac{dQ}{dt}=0

All other choices available aren't related to that same scenario in question. So the answer above is the perfect one.

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Myoncedyret
konstantin123 [22]

Answer:

i need help too

Explanation:

8 0
3 years ago
A ball is dropped from rest at point O . It passes a window with height 3.8 m in time interval tAB = 0.02 s.Identify the correct
Taya2010 [7]

Answer:

VB − VA = g tAB   &   (VA + VB)/2 = h / tAB

Explanation:

s = h = Displacement

tAB = t = Time taken

VA = u = Initial velocity

VB = v = Final velocity

a = g = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{3.8-\frac{1}{2}\times 9.8\times 0.02^2}{0.02}\\\Rightarrow u=189.902\ m/s

v=u+at\\\Rightarrow v=189.902+9.8\times 0.02\\\Rightarrow v=190.098\ m/s

\frac{v+u}{2}=\frac{190.098+189.902}{2}=190\ s

\frac{h}{t}=\frac{3.8}{0.02}=190\ s

Hence, the equations VB − VA = g tAB   &   (VA + VB)/2 = h / tAB will be used

3 0
3 years ago
When a potential difference of 10 V is placed across a certain solid cylindrical resistor, the current through it is 2 A. If the
Keith_Richards [23]

Answer:

New Resistance = 0.5556 ohm

Explanation:

Resistance = resistivity * length /area

Here since resistivity and length are constant, we only need to see how the resistance increases or decreases with change in area.

New Area = pi * (3*D)^2 / 4

Old Area = pi * D^2 / 4

The ratio of new area / old area is :

\frac{New Area}{Old Area} = 9

Since area increases 9 times, and it is inversely proportional to resistance:

Resistance decreases by 9 times.

So, old resistance = Voltage / Current = 10 / 2 = 5 ohm

New Resistance = 5 / 9 = 0.5556 ohm    (decreases by 9 times)

8 0
2 years ago
The near point of an eye is 110 cm. A corrective lens is to be used to allow this eye to focus clearly on objects 26.0 cm in fro
irga5000 [103]

Answer:

The focal length of the lens is 34.047 cm

The power of the needed corrective lens is 2.937 diopter.

Explanation:

Distance of the object from the lens,u = 26 cm

Distance of the image from the lens ,v= -110 cm

(Image is forming on the other side of the lens)

Since ,lens of the human eye is converging lens,convex lens.

Using a lens formula:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{26 cm}+\frac{1}{-110 cm}

f = 34.047 cm = 0.3404 m

Power of the lens = P

P=\frac{1}{f}=\frac{1}{0.34047 m}=2.937 diopter

6 0
2 years ago
You decide to ride your bike for 30 minutes, raising your heart rate to the middle of your target heart rate zone. What type of
a_sh-v [17]
It would have to be cardio i think not totally sure
4 0
3 years ago
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