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Answer:
The value of impulse of the net force on the ball during its collision with wall is
The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N
Explanation:
Mass of the ball = 0.5 kg
Horizontal velocity = 20
Velocity after collision = - 10
(A). Impulse of the net force on the ball during its collision with wall is
I = 0.5 × (20 + 10)
This is the value of impulse of the net force on the ball during its collision with wall.
(B). The magnitude of average horizontal force
Where F = Force
I = impulse & t = time interval = 0.001 sec
F = 15000 N
This is the value of average horizontal force that the wall exerts on the ball during the impact.
The gravitational force on two objects can be determined by the following equation:
Where G is the gravitational constant m1 is mass 1, m2 is the second mass nad r^2 is distance between these objects. Therefore, let m1 = mass of Sun 1.99x10^30 kg, m2= mass of Jupiter 1.90x10^27 kg, r is the average distance between the Sun and Jupiter 7.78x10^11 m. By plugging these values in we have:
F=4.17x10^23 N