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ioda
3 years ago
15

PLEASE HELP!!! PLEASE HELP!!!

Physics
1 answer:
otez555 [7]3 years ago
5 0
It’s d and I kind of agree with b too
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explain why the different thermal conductivities of metal and plastic are important in the design of the bowl.
ololo11 [35]

Answer:

metal conducts heat faster than wood. which means the metal conducted heat away from your hand (or whatever it is) faster than wood.

Explanation:

just because they feel warm/cold doesn't always mean that it is warm/cold. if they both were sitting at room temp for a long time, then both will eventually reach the temp of the room. even though they are the same temp the metal will feel colder than the wood because of the thermal conductivity of the metal compared to the wood.

5 0
2 years ago
A spherical, non-conducting shell of inner radius = 10 cm and outer radius = 15 cm carries a total charge Q = 13 μC distributed
Vaselesa [24]

Answer:

E = 1580594.95 N/C

Explanation:

To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:

\int EdS=\frac{Q_{in}}{\epsilon_o}   (1)

dS: differential of the Gaussian surface

Qin: charge inside the Gaussian surface

εo: dielectric permittivity of vacuum =  8.85 × 10-12 C2/N ∙ m2

The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:

\int EdS=ES=E(4\pi r^2)   (2)

Qin is calculate by using the charge density:

Q_{in}=V_{in}\rho=\frac{4}{3}(r^3-a^3)\rho  (3)

Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.

The charge density is given by:

\rho=\frac{Q}{V}=\frac{13*10^{-6}C}{\frac{4}{3}\pi((0.15m)^3-(0.10m)^3)}\\\\\rho=1.30*10^{-3}\frac{C}{m^3}

Next, you use the results of (3), (2) and (1):

E(4\pi r^2)=\frac{4}{3\epsilon_o}(r^3-a^3)\rho\\\\E=\frac{\rho}{3\epsilo_o}(r-\frac{a^3}{r^2})

Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:

E=\frac{1.30*10^{-3}C/m^3}{3(8.85*10^{-12}C^2/Nm^2)}((0.112m)-\frac{(0.10)^3}{(0.112m)^2})\\\\E=1,580,594.95\frac{N}{C}

hence, the electric field is 1580594.95 N/C

7 0
3 years ago
Using the information from the previous problem (A 2kg ball rotates on the end of a 1.4m long string. The ball makes 5 revolutio
valina [46]

The centripetal force on the ball is 140.9 N; option A

<h3>What is the centripetal force on the ball?</h3>

The centripetal force on the ball is given by the formula below:

  • F = mv²/r

where;

  • m is mass
  • v is linear velocity
  • r is radius

The linear velocity, v = wr

v = 5 * 2π/4.4 * 1.4 = 9.93 m/s

F = 10² * 2/1.4 = 140.9 N

In conclusion, the centripetal force is derived from the mass, velocity and radius of the path.

Learn more about centripetal force at: brainly.com/question/20905151

#SPJ1

6 0
2 years ago
Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197
Leno4ka [110]

(a) 3.58 km 45° south of east

The total displacement is given by:

d=vt

where

v is the average velocity

t is the time

The average velocity is:

v = 3.53 m/s

While we need to convert the time from minutes to seconds:

t=169 min \cdot 60 s/min = 10140 s

Therefore, the magnitude of the displacement is

d=(3.53)(10140)=35794 m = 3.58 km

And the direction is the same as the velocity, therefore 45° south of east.

(b) 5.53 m/s 90° south of east

The velocity of the air relative to the ground is

v_a = 2.00 m/s

and the direction is exactly opposite to that of Allen, so it is 45° north of west. Allen's velocity relative to the ground is

v = 3.53 m/s

So this must be the resultant of Allen's velocity relative to the air (v') and the air's speed (v_a). Since these two vectors are in opposite direction, we have

v= v'-v_a

Therefore we find v', Allen's velocity relative to the air:

v'=v+v_a = 3.53 + 2.00 = 5.53 m/s

The direction must be measured relative to the air's reference frame. In this reference frame, Allen is moving exactly backward, so his direction will be 90° south of east.

(c) 56.1 km at 90° south of east.

Since Allen's velocity relative to the air is

v' = 5.53 m/s

Then the displacement of Allen relative to the air will be given by

d'=v't

and substituting,

d'=(5.53)(10140)=56074 m = 56.1 km

And the direction is the same as that of the velocity, therefore will be 90° south of east.

3 0
3 years ago
What type of simple machine is found in a wheelbarrow?<br><br> Lever<br><br> Wedge
Semenov [28]

Answer: Lever

A wheelbarrow consists of a lever to be able to lift the material, and a wheel to be able to move it horizontally. So in a sense, a wheelbarrow is a complex machine consisting of two simple machines.

8 0
3 years ago
Read 2 more answers
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