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riadik2000 [5.3K]
3 years ago
6

1, Can bed bugs adapt to the heat treatments? Why or why not?

Physics
1 answer:
mart [117]3 years ago
6 0

Answer:

Heat radiates into walls and your belongings to get bed bugs in places that are hard to get to with insecticides Hope It Helps

Explanation:

Studies have shown that bed bugs can become resistant to chemicals and adapt to living in dangerous environments. This can make it a difficult job to treat for bed bugs with chemical products.

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A 260-kg glider is being pulled by a 1,940-kg jet along a horizontal runway with an acceleration of a= 2.20 m/s^2 to the right.
lisov135 [29]

Answer:

a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

Explanation:

a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:

Jet

\Sigma F = F - T = m_{J}\cdot a (1)

Glider

\Sigma F = T = m_{G}\cdot a (2)

Where:

F - Thrust of jet engines, measured in newtons.

T - Tension in the cable connecting the jet and glider, measured in newtons.

m_{G}, m_{J} - Masses of the glider and the jet, measured in kilograms.

a - Acceleration of the glider-jet system, measured in meters per square second.

If we know that m_{G} = 260\,kg, m_{J} = 1,940\,kg and a = 2.20\,\frac{m}{s^{2}}, then the solution of this system of equations:

By (2):

T = (260\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

T = 572\,N

By (1):

F = T+m_{J}\cdot a

F = 572\,N+(1,940\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

F = 4840\,N

The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

7 0
3 years ago
What happens to the current supplied by the battery when you add an identical bulb in parallel to the original bulb?
Marysya12 [62]

Answer:

b. The current stays the same.

Explanation:

In the case given current is supplied by the battery to a bulb . Here, we should know that bulb also apply resistance to the flow of current .

Now, when an identical bulb is connected in parallel to the original bulb .

Therefore, both the resistance( bulb) are in parallel.

We know, when two resistance are in parallel , current through them is same and voltage is divided between them.

Therefore, in this case current stays same in the original bulb.

Hence, this is the required solution.

6 0
3 years ago
SOMEONE PLEASEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPP
Evgen [1.6K]

Answer:

53.33 seconds

Explanation:

From the question;

  • Power of the motor is 75 kW or 75000 W
  • Depth or height is 150 m
  • Volume of water is 400 m³

We are required to determine taken to raise the water from the given height.

We know that density of water is 1000 kg/m³

Therefore;

Mass of water = 400 m³ × 1000 kg/m³

                       = 4.0 × 10^5 kg

Thus, force required to raise the water;

 = 4.0 × 10^5 kg × 10 N/kg

  = 4.0 × 10^6 N

To determine the time;

we use the formula;

 Time = work done ÷ power  

          = (4.0 × 10^6 N × 150 m) ÷ 75000 Joules/s

          = 53.33 seconds

Therefore, time taken to raise the water is 53.33 seconds

8 0
3 years ago
I need help fast! !!!
I am Lyosha [343]
I think it would be at 3 or 6 but I would go with 3 not really sure tho
3 0
3 years ago
A pilot performs an evasive maneuver by diving vertically at 270. If he can withstand an acceleration of 9.0 's without blacking
mamaluj [8]

Answer:

The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

Explanation:

Given that,

Velocity = 270 m/s

Acceleration = 9.0g s

We need to calculate the altitude

Using formula of centripetal acceleration

a_{c}=\dfrac{v^2}{r}

r=\dfrac{v^2}{a_{c}}

Where, v = velocity

r = altitude

a = acceleration

Put the value into the formula

r=\dfrac{270^2}{9.0\times9.8}

r=826.53\ m

Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

6 0
3 years ago
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