Answer:
The mass percent of Al(OH)₃ is 15.3%
Explanation:
The reaction is:
Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O
The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:
NaOH + HCl = NaCl + H₂O
The total moles of HCl is:
From the second titration, the moles of excess of HCl is:
The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:
The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:
The percentage of Al(OH)₃ is:
%
Answer:
phosphodiester bond
Explanation:
<em>Phosphodiester linkage/bond is found in deoxyribonucleic and ribonucleic acids. It is formed from a reaction involving the elimination of water from a reaction involving the hydroxyl groups of two different 5-carbon (pentose) sugars and a phosphate group.</em>
The elimination of water, also known as condensation reaction occur twice, resulting in the formation of two ester bonds which then bind the phosphate group to the pentose sugars to become a phosphodiester bond.
The bond links the 3'-hydroxyl group of one of the pentose sugars and the 5'-hydroxyl group of the other pentose sugar in the nucleotides that make up nucleic acids.
D. uranium: atomic number 92, mass 238, neutrons 146
238-92=146
Answer:
The answer to your question is 7.64 atm
Explanation:
Data
Volume 1 = V1 = 2.1 l
moles = 4.65
Pressure 1 = P1 = 3.82 atm
Volume 2 = Volume 1/2
Pressure 2 = ?
Process
1.- Calculate the new volume
Volume 2 = 2.10/2
Volume 2 = 1.05 l
2.- Use Boyle's law to find the Pressure
P1V1 = P2V2
-Solve for P2
P2 = P1V1 / V2
-Substitution
P2 = (3.82)(2.1) / 1.05
-Simplification
P2 = 8.022/1.05
-Result
P2 = 7.64 atm
