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Vaselesa [24]
4 years ago
6

A rifle of mass M is initially at rest. A bullet of mass m is fired from the rifle with a velocity of v relative to the ground.

What is the expression that gives the velocity of the rifle relative to the ground after the bullet is fired?
Physics
1 answer:
Iteru [2.4K]4 years ago
7 0

Answer:

V_{rifle} = -\frac{mV_{bullet} }{M}.

Explanation:

According to conservation of momentum, the momentum of rifle before fire is equal to the momentum of bullet after fire plus momentum of rifle after fire.

This in mathematics translates to.

(M+m)v_{rifle-before-fire}=Mv_{rifle-after-fire}+mv_{bullet}

rifle is stationary before fire so v_{rifle-before-fire}=0  this means that left side is 0.

0=Mv_{rifle-after-fire}+mv_{bullet}

solving for v_{rifle-after-fire} in above gives us our answer.

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The answer is the letter A.
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3 years ago
Terry can ride 30 miles in 2 hours. If his riding speed is
Anni [7]

Answer:  20.4 miles

Explanation:

Here we need to use the equation:

Velocity = Distance/Time.

Initially we have that he can travel 30 miles in 2 hours, so the velocity is:

V = 30mi/2h = 15mph

Now, we reduce the velocity by 3 mph, so the new velocity is 15mph - 3 mph = 12mph.

Now we want to know the distance traveled in 1.7 hours with this velocity, this is.

Velocity*Time = Distance

12mi/h*1.7h = 20.4 miles

7 0
3 years ago
Why does the frequency of a siren get higher as an ambulance using that siren gets closer?
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The answer is D. As the ambulance gets closer, the sound waves are compressed relative to the person; so the frequency increases.

7 0
3 years ago
Read 2 more answers
Beat frequency problem. Your ear simultaneously hears waves from different sources, so it can hear beats from the two speakers.
podryga [215]

Completed question:Suppose one speaker is driven at 570 Hz and the other at 554 Hz. What is the beat frequency in Hz? The average frequency in Hz?

Answer:

Beat frequency= 16Hz

Average frequency = 562Hz

Explanation:

Beat frequency f = f2-f1

Where f2 is frequency of source with higher frequency

           f1 is frequency of source with lower frequency

          f1= 554Hz, f2= 570Hz

   beat frequency (f) = 570 -554

                                  = 16Hz

   Average frequency = \frac{554+570}{2}

                                    =\frac{1124}{2}\\ =562Hz

5 0
3 years ago
Two capacitors of 36 µF and 3.8 µF are connected parallel and charged with a 51 V power supply. Calculate the total energy store
olga nikolaevna [1]

Answer:

 U=0.0517 J

Explanation:

Given that

The values of capacitance

C₁ = 36 µF

C₂ =  3.8 µF

We know that when capacitor are connected in the parallel then the equivalent value of the capacitance is given as

C=C₁ +C₂

Now by putting the values

C= 36 + 3.8 µF

C = 39.8 µF

The voltage difference

ΔV= 51 V

The total stored energy in capacitor is given as

U=\dfrac{1}{2}C\Delta V^2

Now by putting the values in the above equation we get

U=\dfrac{1}{2}\times 39.8\times 10^{-6}\times 51^2\ J

U=0.0517 J

Therefore the stored energy in the capacitors will be 0.0517 J.

4 0
3 years ago
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