The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M
<h3>Balanced equation </h3>
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
<h3>How to determine the molarity of HCl </h3>
- Molarity of base, NaOH (Mb) = 0.137 M
- Volume of base, NaOH (Vb) = 16.1 mL
- Volume of acid, HCl (Va) = 27.9 mL
- Molarity of acid, HCl (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 27.9) / (0.137 × 16.1) = 1
(Ma × 27.9) / 2.2057 = 1
Cross multiply
Ma × 27.9 = 2.2057
Divide both side by 27.9
Ma = 2.2057 / 27.9
Ma = 0.079 M
Thus, the molarity of the HCl solution is 0.079 M
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Answer: 35.4 g
Explanation:
The balanced reaction is :
To calculate the moles :
According to stoichiometry :
2 moles of phosphorous chloride are produced by = 3 moles of 
Thus 0.37 moles of phosphorous chloride are produced by=
of
Mass of 
Thus 35.4 g of chlorine reacted with the phosphorus
One half of the distance between the nuclei of two atoms bonded together by a single bond is known as the covalent bond radius. When a covalent bond is present between atoms, this radius can be determined. It is the radius of the two atoms because they are equally attracted.
